[英]Zip file is getting corrupted after downloading from server in C#
request = MakeConnection(uri, WebRequestMethods.Ftp.DownloadFile, username, password);
response = (FtpWebResponse)request.GetResponse();
Stream responseStream = response.GetResponseStream();
//This part of the code is used to write the read content from the server
using (StreamReader responseReader = new StreamReader(responseStream))
{
using (var destinationStream = new FileStream(toFilenameToWrite, FileMode.Create))
{
byte[] fileContents = Encoding.UTF8.GetBytes(responseReader.ReadToEnd());
destinationStream.Write(fileContents, 0, fileContents.Length);
}
}
//This part of the code is used to write the read content from the server
using (var destinationStream = new FileStream(toFilenameToWrite, FileMode.Create))
{
long length = response.ContentLength;
int bufferSize = 2048;
int readCount;
byte[] buffer = new byte[2048];
readCount = responseStream.Read(buffer, 0, bufferSize);
while (readCount > 0)
{
destinationStream.Write(buffer, 0, readCount);
readCount = responseStream.Read(buffer, 0, bufferSize);
}
}
前者將內容寫入文件,但是當我嘗試打開文件時,它說文件已損壞。 但是后面的一個下載zip文件時做得很好。 有什么特定的原因為什么以前的代碼不能完美地適用於文本文件,而無法用於zip文件?
byte[] fileContents = Encoding.UTF8.GetBytes(responseReader.ReadToEnd());
您嘗試將二進制PDF文件解釋為UTF-8文本。 那根本行不通。
有關正確的代碼,請參見在C#/。NET中將二進制文件上傳到FTP服務器或從FTP服務器下載二進制文件 。
使用BinaryWriter並將其傳遞給FileStream。
//This part of the code is used to write the read content from the server
using (var destinationStream = new BinaryWriter(new FileStream(toFilenameToWrite, FileMode.Create)))
{
long length = response.ContentLength;
int bufferSize = 2048;
int readCount;
byte[] buffer = new byte[2048];
readCount = responseStream.Read(buffer, 0, bufferSize);
while (readCount > 0)
{
destinationStream.Write(buffer, 0, readCount);
readCount = responseStream.Read(buffer, 0, bufferSize);
}
}
這是對我有用的解決方案
C#
public IActionResult GetZip([FromBody] List<DocumentAndSourceDto> documents)
{
List<Document> listOfDocuments = new List<Document>();
foreach (DocumentAndSourceDto doc in documents)
listOfDocuments.Add(_documentService.GetDocumentWithServerPath(doc.Id));
using (var ms = new MemoryStream())
{
using (var zipArchive = new ZipArchive(ms, ZipArchiveMode.Create, true))
{
foreach (var attachment in listOfDocuments)
{
var entry = zipArchive.CreateEntry(attachment.FileName);
using (var fileStream = new FileStream(attachment.FilePath, FileMode.Open))
using (var entryStream = entry.Open())
{
fileStream.CopyTo(entryStream);
}
}
}
ms.Position = 0;
return File(ms.ToArray(), "application/zip");
}
throw new ErrorException("Can't zip files");
}
不要錯過ms.Position = 0;
這里
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