[英]Passing id through an link href in Laravel
是否可以通過 Laravel 中的鏈接 href 傳遞 id 並顯示該頁面,如 /projects/display/2。
我有這個鏈接:
<td><a href="{{ url('projects/display', $projects->id) }}" class="btn btn-info">View</a></td>
當鼠標懸停在鏈接上時,它會顯示 id 作為 /projects/display/2。 但是每當我點擊鏈接時,我都會收到一條錯誤消息:
Sorry, the page you are looking for could not be found.
我有一個名為項目/顯示的視圖設置,加上路由和 controller。
路線:
<?php
Route::group(['middleware' => ['web']], function (){
Route::get('/', 'PagesController@getIndex');
Route::get('/login', 'PagesController@getLogin');
Auth::routes();
Route::get('/home', 'HomeController@index');
Route::get('/projects/display', 'ProjectsController@getDisplay');
Route::resource('projects', 'ProjectsController');
});
Controller:
<?php
namespace App\Http\Controllers;
use App\project;
use App\Http\Requests;
use Illuminate\Http\Request;
use Session;
class ProjectsController extends Controller
{
public function index()
{
}
public function create()
{
return view('projects.create');
}
public function store(Request $request)
{
$this->validate($request, array(
'name' => 'required|max:200',
'description' => 'required'
));
$project = new project;
$project->name = $request->name;
$project->description = $request->description;
$project->save();
Session::flash('success', 'The project was successfully created!');
return redirect()->route('projects.show', $project->id);
}
public function show()
{
$project = Project::all();
return view('projects.show')->withProject($project);
}
public function edit($id)
{
//
}
public function update(Request $request, $id)
{
//
}
public function getDisplay($id){
$project = Project::find($id);
return view('projects/display')->withProject($project);
}
}
您需要將路線更改為:
Route::get('/projects/display/{id}', 'ProjectsController@getDisplay');
然后生成URL:
{{ url('projects/display/'.$projects->id) }}
如果你寫下面的路線,
Route::get('/projects/display/{projectId}', 'ProjectsController@getDisplay')->name('displayProject');
您可以在href中使用名稱'displayProject'並將id作為Array傳遞:
<td><a href="{{ route('displayProject', ['projects' => $projects->id]) }}" class="btn btn-info">View</a></td>
您正在尋找的是參數化路線。 在這里閱讀更多相關信息: https : //laravel.com/docs/5.3/routing#required-parameters
我找到了一個更好的解決方案:在你的刀片文件中這樣做
<a href="{{route('displayProject',"$id")}}">
View
</a>
使用這條路線,在路線文件中
Route::get('/projects/display/{id}', 'ProjectsController@getDisplay');
$id 是從你的 controller 發送的
return view('viewPage', compact('id'));
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