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通过 Laravel 中的链接 href 传递 id

[英]Passing id through an link href in Laravel

is it possible to pass id through an link href in Laravel and display that page like /projects/display/2.是否可以通过 Laravel 中的链接 href 传递 id 并显示该页面,如 /projects/display/2。

I have this link:我有这个链接:

<td><a href="{{ url('projects/display', $projects->id) }}" class="btn btn-info">View</a></td>

It displays the id when hovering over the link as /projects/display/2.当鼠标悬停在链接上时,它会显示 id 作为 /projects/display/2。 But whenever i click on the link i get an error message of:但是每当我点击链接时,我都会收到一条错误消息:

 Sorry, the page you are looking for could not be found.

I have a view setup called projects/display, plus routes and controller.我有一个名为项目/显示的视图设置,加上路由和 controller。

routes:路线:

<?php


Route::group(['middleware' => ['web']], function (){

    Route::get('/', 'PagesController@getIndex');

    Route::get('/login', 'PagesController@getLogin');

    Auth::routes();

    Route::get('/home', 'HomeController@index');

    Route::get('/projects/display', 'ProjectsController@getDisplay');

    Route::resource('projects', 'ProjectsController');


});

Controller: Controller:

<?php

namespace App\Http\Controllers;

use App\project;
use App\Http\Requests;
use Illuminate\Http\Request;
use Session;

class ProjectsController extends Controller
{

    public function index()
    {



    }


    public function create()
    {
        return view('projects.create');
    }



    public function store(Request $request)
    {
        $this->validate($request, array(

            'name' => 'required|max:200',
            'description' => 'required'
        ));

        $project = new project;

        $project->name = $request->name;
        $project->description = $request->description;

        $project->save();

         Session::flash('success', 'The project was successfully created!');

        return redirect()->route('projects.show', $project->id);


    }


    public function show()
    {
        $project = Project::all(); 

        return view('projects.show')->withProject($project);

    }


    public function edit($id)
    {
        //
    }


    public function update(Request $request, $id)
    {
        //
    }

    public function getDisplay($id){


        $project = Project::find($id);

        return view('projects/display')->withProject($project);

    }





}

You need to change your route to: 您需要将路线更改为:

Route::get('/projects/display/{id}', 'ProjectsController@getDisplay');

And then generate URL with: 然后生成URL:

{{ url('projects/display/'.$projects->id) }}

If you write route like below, 如果你写下面的路线,

Route::get('/projects/display/{projectId}', 'ProjectsController@getDisplay')->name('displayProject');

You can use the name 'displayProject' in the href and pass the id as Array : 您可以在href中使用名称'displayProject'并将id作为Array传递:

<td><a href="{{ route('displayProject', ['projects' => $projects->id]) }}" class="btn btn-info">View</a></td>

What you are looking for is a parameterized route. 您正在寻找的是参数化路线。 Read more about them here: https://laravel.com/docs/5.3/routing#required-parameters 在这里阅读更多相关信息: https//laravel.com/docs/5.3/routing#required-parameters

I found a better solution: In your blade file do like this我找到了一个更好的解决方案:在你的刀片文件中这样做

<a href="{{route('displayProject',"$id")}}">
  View
</a>

with this route, in route file使用这条路线,在路线文件中

Route::get('/projects/display/{id}', 'ProjectsController@getDisplay');

$id is sent form your controller with compact $id 是从你的 controller 发送的

return view('viewPage', compact('id'));

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