[英]XML file to datagridview c#
我正在使用一個API,該API返回以XML格式保存的XML文件中的文本。 每當我嘗試將信息顯示到datagridview時。 但是我收到一個錯誤消息,說該文件已經打開並正在使用。 這是接收文本,將其保存到XML並嘗試將其顯示到數據網格的代碼。
using (WebResponse response = request.GetResponse())
{
using (Stream stream = response.GetResponseStream())
{
using (StreamReader sr99 = new StreamReader(stream))
{
responseContent = sr99.ReadToEnd();
}
}
}
XmlDocument doc = new XmlDocument();
doc.LoadXml(responseContent);
XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;
// Save the document to a file and auto-indent the output.
XmlWriter writer = XmlWriter.Create("ResponseContent.xml", settings);
doc.Save(writer);
XmlReader xmlFile = XmlReader.Create(@"C:\Users\Tyler\Documents\Repo\New Trunk\WalmartSmiles\WalmartSmiles\bin\Debug\ResponseContent.xml", new XmlReaderSettings());
DataSet dataSet = new DataSet();
//Read xml to dataset
dataSet.ReadXml("ResponseContent.xml");
//Pass empdetails table to datagridview datasource
dataGridView1.DataSource = dataSet.Tables["ns2:feed"];
//Close xml reader
xmlFile.Close();
XmlReader xmlFile ;
xmlFile = XmlReader.Create("Product.xml", new XmlReaderSettings());
DataSet ds = new DataSet();
ds.ReadXml(xmlFile);
dataGridView1.DataSource = ds.Tables[0];
將數據傳遞到dataGridView的簡單方法
通常,發生這種情況時,請在代碼中查找其他也已打開,讀取,寫入或對該文件執行任何操作的其他事物,然后將其關閉!
// Save the document to a file and auto-indent the output.
XmlWriter writer = XmlWriter.Create("ResponseContent.xml", settings);
doc.Save(writer);
writer.Close();
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