通過python在運行shell腳本中找不到文件

Question

我有一個python腳本，在代碼的單個部分中，必須執行一個終端命令，這是代碼：

# run shell script and return response printed
def run_shell(command_string):
    p = subprocess.Popen([command_string], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
    return p.communicate()

這是獲取命令並運行該命令的特定函數。 例如，當輸入為“查找”（以遞歸方式列出文件和目錄）時，輸出為：

./actions
./actions/scripts
./actions/scripts/script_aa00.py
./log_list_template.json
./README.md
./.git
./main
./main/Classifier.py
./main/Solver.py
./main/learner.py
./main/Database.py
./main/__pycache__
./main/__pycache__/Database.cpython-35.pyc
./main/__pycache__/learner.cpython-35.pyc
./start.sh
./run.py
./signals
./signals/scripts
./signals/scripts/script_aa00.py  [I want to run this script]
./signals/list0.json
./signals/template.json

但是當輸入為“ python3 signals / scripts / script_aa00.py ”時，輸出包含一個錯誤，表示未找到script_aa00.py。 當我嘗試“ python3 signals / scripts / script_aa00.py ”時，我自己在終端（在此目錄中）工作正常

Answer 1

您可以嘗試將shell=true添加到Popen和/或使用絕對路徑：

p = subprocess.Popen(['/usr/bin/python3', '/home/.../signals/scripts/script_aa00.py'], shell=true, stdout=subprocess.PIPE, ...)