[英]file not found in running shell script through python
我有一个python脚本,在代码的单个部分中,必须执行一个终端命令,这是代码:
# run shell script and return response printed
def run_shell(command_string):
p = subprocess.Popen([command_string], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
return p.communicate()
这是获取命令并运行该命令的特定函数。 例如,当输入为“查找”(以递归方式列出文件和目录)时,输出为:
./actions
./actions/scripts
./actions/scripts/script_aa00.py
./log_list_template.json
./README.md
./.git
./main
./main/Classifier.py
./main/Solver.py
./main/learner.py
./main/Database.py
./main/__pycache__
./main/__pycache__/Database.cpython-35.pyc
./main/__pycache__/learner.cpython-35.pyc
./start.sh
./run.py
./signals
./signals/scripts
./signals/scripts/script_aa00.py [I want to run this script]
./signals/list0.json
./signals/template.json
但是当输入为“ python3 signals / scripts / script_aa00.py ”时,输出包含一个错误,表示未找到script_aa00.py。 当我尝试“ python3 signals / scripts / script_aa00.py ”时,我自己在终端(在此目录中)工作正常
您可以尝试将shell=true
添加到Popen和/或使用绝对路径:
p = subprocess.Popen(['/usr/bin/python3', '/home/.../signals/scripts/script_aa00.py'], shell=true, stdout=subprocess.PIPE, ...)
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