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如何在C#中聲明LARGE_INTEGER

[英]How to declarate LARGE_INTEGER in C#

下面的代碼(在C ++中)是我嘗試轉換為C#

DWORD Func_X_4(DWORD arg1, DWORD arg2, DWORD arg3)
{
LARGE_INTEGER result = {1, 0};
LARGE_INTEGER temp1 = {0};
LARGE_INTEGER temp2 = {0};
LARGE_INTEGER temp3 = {0};
LARGE_INTEGER temp4 = {0};
for(int x = 0; x < 32; ++x)
{
    if(arg2 & 1)
    {
        temp1.LowPart = arg3;
        temp1.HighPart = 0;
        temp2.QuadPart = temp1.QuadPart * result.QuadPart;
        temp3.LowPart = arg1;
        temp3.HighPart = 0;
        temp4.QuadPart = temp2.QuadPart % temp3.QuadPart;
        result.QuadPart = temp4.QuadPart;
    }
    arg2 >>= 1;
    temp1.LowPart = arg3;
    temp1.HighPart = 0;
    temp1.QuadPart *= temp1.QuadPart;
    temp2.LowPart = arg1;
    temp2.HighPart = 0;
    temp3.QuadPart = temp1.QuadPart % temp2.QuadPart;
    arg3 = temp3.LowPart;
    if(!arg2)
        break;
}
return result.LowPart;
}

在這里,我嘗試翻譯代碼,但它太亂了,我之前從未使用過大整數。

結構體:

public struct LARGE_INTEGER
{
    UInt32 LowPart;
    Int32 HighPart;
    Int32 QuadPart;
}

翻譯功能:

    public Int32 Func_X_4(Int32 arg1, Int32 arg2, Int32 arg3)
    {
    LARGE_INTEGER result = {1, 0}; //this and the four below,are they correct?
    LARGE_INTEGER temp1 = {0, 0};
    LARGE_INTEGER temp2 = {0, 0};
    LARGE_INTEGER temp3 = {0, 0};
    LARGE_INTEGER temp4 = {0, 0};
    for(int x = 0; x < 32; ++x)
    {
        if(arg2 & 1==0) //correct?
        {
            temp1.LowPart = arg3;
            temp1.HighPart = 0;
            temp2.QuadPart = temp1.QuadPart * result.QuadPart;
            temp3.LowPart = arg1;
            temp3.HighPart = 0;
            temp4.QuadPart = temp2.QuadPart % temp3.QuadPart;
            result.QuadPart = temp4.QuadPart;
        }
        arg2 >>= 1;
        temp1.LowPart = arg3;
        temp1.HighPart = 0;
        temp1.QuadPart *= temp1.QuadPart;
        temp2.LowPart = arg1;
        temp2.HighPart = 0;
        temp3.QuadPart = temp1.QuadPart % temp2.QuadPart;
        arg3 = temp3.LowPart;
        if(arg2 != 0) //correct?
        break;
    }
    return result.LowPart;
}

問題:第一個問題是我沒有在C#中找到一個LARGE_INTEGER類型變量,所以我創建了一個結構,我想知道是否確實存在。 至於第二個問題,功能不對,沒有用。

任何有關該特定問題的幫助都將非常感謝! 先感謝您。

LARGE_INTEGER結構的直接轉換是:

[StructLayout(LayoutKind.Explicit, Size=8)]
struct LARGE_INTEGER
{
    [FieldOffset(0)]public Int64 QuadPart;
    [FieldOffset(0)]public UInt32 LowPart;
    [FieldOffset(4)]public Int32 HighPart;
}

它就像C中的聯合 ,其中QuadPart是一個8字節的值, LowPart占用前4個字節, HighPart占用高4個字節。

它的Int64。 基於http://msdn.microsoft.com/en-us/library/aa383713.aspx ,它是一個64位有符號整數。

基於之前的答案,我發現擴展LARGE_INTEGER的定義以包含高和低部分的int和uint版本是有用的:

[StructLayout(LayoutKind.Explicit, Size=8)]
struct LARGE_INTEGER
    {
    [FieldOffset(0)]public long QuadPart;

    [FieldOffset(0)]public uint LowPart;
    [FieldOffset(4)]public int HighPart;

    [FieldOffset(0)]public int LowPartAsInt;
    [FieldOffset(0)]public uint LowPartAsUInt;

    [FieldOffset(4)]public int HighPartAsInt;
    [FieldOffset(4)]public uint HighPartAsUInt;
    }

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