[英]Change the x axis values of graph c#
我對c#和Visual Studio有點新,我試圖根據位於其他地方的csv文件的值繪制圖形。 我在c#中使用了ChartObjects和ChartWizard屬性來創建圖形。 繪制的圖表應該是我提供的列范圍,在Y軸和X軸應該具有當前行號(1,2,3,4等)。 但是我的圖表默認情況下將X軸作為我的csv文件中的第一列。 如果我也為X軸指定了一個范圍,那么它會正確繪制但是如何獲得當前的行號呢?
我甚至在Stack Overflow上經歷了很多文章和問題,但似乎沒有任何幫助。
這是我的代碼片段:
Microsoft.Office.Interop.Excel.Application xlexcel;
Microsoft.Office.Interop.Excel.Worksheet xlWorkSheet;
object misValue = System.Reflection.Missing.Value;
xlexcel = new Microsoft.Office.Interop.Excel.Application();
var xlWorkBooks = xlexcel.Workbooks;
xlexcel.Visible = false;
xlWorkBooks.OpenText(@"C:\" + processName + ".csv", misValue, misValue, Microsoft.Office.Interop.Excel.XlTextParsingType.xlDelimited, Microsoft.Office.Interop.Excel.XlTextQualifier.xlTextQualifierNone, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue);
// Set Sheet 1 as the sheet you want to work with
xlWorkSheet = (Microsoft.Office.Interop.Excel.Worksheet)xlWorkBooks[1].Worksheets.get_Item(1);
xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select();
//~~> Make it a Line Chart
xlexcel.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine);
//~~> Set the data range
xlexcel.ActiveChart.SetSourceData(xlWorkSheet.Range["E2:E200"]);
xlexcel.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType);
Microsoft.Office.Interop.Excel.ChartObjects chartObjects =(Microsoft.Office.Interop.Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing));
foreach (Microsoft.Office.Interop.Excel.ChartObject co in chartObjects)
{
co.Select();
Microsoft.Office.Interop.Excel.Chart chart = (Microsoft.Office.Interop.Excel.Chart)co.Chart;
chart.Export(ConfigurationManager.AppSettings.Get("Charts") + "\\ProcessFiles" + @"\" + chartName + " (" + processName + "of" + processType + ")" + ".png", "PNG", false);
co.Delete();
}
xlWorkBooks[1].Close(true, misValue, misValue);
xlexcel.Quit();
任何指導將不勝感激。 謝謝!
我嘗試了你的代碼並進行了一些修改,我希望這會有效
using Excel = Microsoft.Office.Interop.Excel;
Excel.Application xlApp;
Excel.Workbook xlWorkBook;
Excel.Worksheet xlWorkSheet;
object misValue = System.Reflection.Missing.Value;
//string appPath = Path.GetDirectoryName(Application.ExecutablePath);
string fileName = "" + "YOUR_PATH" + "\\Templates\\myCSV.csv";
string processName = "test";
xlApp = new Excel.Application();
xlWorkBook = xlApp.Workbooks.Open(fileName);
xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1);
xlWorkSheet.Shapes.AddChart(misValue, misValue, misValue, misValue, misValue).Select();
//~~> Make it a Line Chart
xlApp.ActiveChart.ApplyCustomType(Microsoft.Office.Interop.Excel.XlChartType.xlLine);
//~~> Set the data range
xlApp.ActiveChart.SetSourceData(xlWorkSheet.Range["B1:B30"]);
string chartName = "TEST CHART", processType="TEST TYPE";
xlApp.ActiveChart.ChartWizard(misValue, Title: chartName + " (" + processName + ")", CategoryTitle: "Iterations", ValueTitle: processType);
Excel.ChartObjects chartObjects = (Excel.ChartObjects)(xlWorkSheet.ChartObjects(Type.Missing));
foreach (Excel.ChartObject co in chartObjects)
{
co.Select();
Excel.Chart chart = (Excel.Chart)co.Chart;
chart.Export("C:\\YOUR_PATH" + @"\" + chart.Name + ".png", "PNG", false);
}
xlWorkBook.Close(true, misValue, misValue);
xlApp.Quit();
xlWorkSheet = null;
xlWorkBook = null;
xlApp = null;
releaseObject(xlWorkBook);
releaseObject(xlWorkSheet);
releaseObject(xlApp);
private void releaseObject(object obj)
{
try
{
System.Runtime.InteropServices.Marshal.ReleaseComObject(obj);
obj = null;
}
catch (Exception ex)
{
obj = null;
MessageBox.Show(ex.Message);
}
finally
{
GC.Collect();
}
}
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