python for矩陣中的循環以分配值

Question

我正在創建一個程序，該程序將創建一個網格，並且該程序將在您在輸入處分配的矩陣數組的位置超出其位置。

碼：

def onbekende_naam(hoogtes):
    print(hoogtes)
    i = 0
    j = 0
    pos1 = set()

    for hoogtes_subs in hoogtes:
        j = 0
        for hoogtes in hoogtes:
            print("i = " + str(i))
            print("j = " + str(j))
            pos1.add((i, j))
            print pos1
            j += 1
        i += 1
        #pos1.add((i, j))

    return pos1

#verwerking
print (onbekende_naam(hoogtes)) 

輸入：

4 4
1 2 3 4
5 6 7 8
9 1 2 3
4 5 6 7
12 1

輸出：

[['1', '2', '3', '4'], ['5', '6', '7', '8'], ['9', '1', '2', '3'], ['4', '5', '6', '7']]
i = 0
j = 0
set([(0, 0)])
i = 0
j = 1
set([(0, 1), (0, 0)])
i = 0
j = 2
set([(0, 1), (0, 0), (0, 2)])
i = 0
j = 3
set([(0, 1), (0, 3), (0, 0), (0, 2)])
i = 1
j = 0
set([(0, 1), (0, 3), (0, 0), (0, 2), (1, 0)])
i = 1
j = 1
set([(0, 1), (0, 0), (0, 2), (1, 0), (0, 3), (1, 1)])
i = 1
j = 2
set([(0, 1), (1, 2), (0, 0), (0, 2), (1, 0), (0, 3), (1, 1)])
i = 1
j = 3
set([(0, 1), (1, 2), (0, 0), (0, 2), (1, 3), (1, 0), (0, 3), (1, 1)])
i = 2
j = 0
set([(0, 1), (1, 2), (0, 0), (0, 2), (2, 0), (1, 3), (1, 0), (0, 3), (1, 1)])
i = 3
j = 0
set([(0, 1), (1, 2), (0, 0), (3, 0), (0, 2), (2, 0), (1, 3), (1, 0), (0, 3), (1, 1)])
set([(0, 1), (1, 2), (0, 0), (3, 0), (0, 2), (2, 0), (1, 3), (1, 0), (0, 3), (1, 1)])

如您所見，當i值大於2時，它將停止遞增j

我在這個方面還很新，所以謝謝你的幫助

Answer 1

看起來您在第二個for循環中使用了相同的名稱。 您可以嘗試更改此方法嗎？

def onbekende_naam(hoogtes):
    print(hoogtes)
    i = 0
    j = 0
    pos1 = set()

    for hoogtes_subs in hoogtes:
        j = 0
        for another_name_hoogtes in hoogtes:
            print("i = " + str(i))
            print("j = " + str(j))
            pos1.add((i, j))
            print pos1
            j += 1
        i += 1
        #pos1.add((i, j))

    return pos1

#verwerking
print (onbekende_naam(hoogtes)) 

另外：當我運行您的原始代碼時，出現以下錯誤：

TypeError：“ int”對象不可迭代

為什么沒有收到此錯誤？