帶有雙引號的字符串替換為帶雙引號的字符串

Question

我正在編寫此軟件，這使我在網站上的工作更加輕松。 我只是輸入了一個腳本，它將用跨度為我突出顯示代碼。 到了那里，但是我有一個問題。 （我目前正在突出顯示UnityC＃）

我希望字符串為黃色，包括雙引號，但是現在嘗試這種方式會導致無限循環。 我知道引號做錯了，但是我不知道那是什么。 請幫我 ：）

原始變量是由std::string original ((istreambuf_iterator<char>(currentFile)), istreambuf_iterator<char>()); ，其中currentFile是我加載的腳本

std::size_t pos = 0;
while(original.find("\"", pos) != std::string::npos)
{
    //find the first occurrence of the quote
    std::size_t found = original.find("\"", pos);
    if(found != std::string::npos)
    {
        //save the start position of the string
        std::size_t start_pos = found;
        //save the end position by searching for the next quotation mark
        std::size_t end_pos = original.find_first_of("\"", start_pos+1);
        //Calculate the size of the string
        std::size_t length = end_pos-start_pos;
        //Make a copy of the word without the quotation marks
        std::string originalWord = original.substr(start_pos+1, length-1);
        //Make the new word with span, original word(without the quotation marks) and add quotation marks around the word
        std::string newWord = std::string("<span class='yellow_code'>") + "\"" + originalWord + "\"" + "</span>";
        std::cout<<originalWord<<" : "<<newWord<<std::endl;
        //Replace the string WITH the quotation marks for the newWord
        original.replace(start_pos, length+1, newWord);
        //Set the position to after the string
        pos = end_pos+1;
    }
    else
    {
        pos = found+1;
    }
}

當我運行它時，它將提示：/dataValues.dat：<span class ='yellow_code'>“ / dataValues.dat” </ span>無限。

怎么了？

問候，丹妮

Answer 1

問題在這里： pos = end_pos + 1; 這可以讓您的索引比字符串短。

讓我們看看您的示例發生了什么：

• 原來original是bla..."/dataValues.dat"...和end_pos是pos + 16
• 替換后，您會得到bla...<span class='yellow_code'>"/dataValues.dat"</span>... end_pos並未更改，並指向黃色的第一個l ！
• 在下一次搜索中，您再次找到相同的帶引號的字符串...

您必須在end_pos添加<span...>和</span>的長度，以使其指向</span>

Answer 2

您沒有添加添加到字符串中的開始和結束標簽的大小。 這是一個如何做的例子

std::string start_tag = "<span class='yellow_code'>";
std::string end_tag = "\"</span>";

std::size_t pos = 0;
while(original.find("\"", pos) != std::string::npos)
{
    std::size_t found = original.find("\"", pos);
    if(found != std::string::npos)
    {
        std::size_t start_pos = found;
        std::size_t end_pos = original.find_first_of("\"", start_pos+1);
        if (end_pos == std::string::npos) // If the number of quotation characters is odd you would get undefined behavior
            break;
        std::size_t length = end_pos - start_pos;
        std::string originalWord = original.substr(start_pos+1, length-1);
        std::string newWord = start_tag + "\"" + originalWord + end_tag; // CHANGED: Added the start and end tags as std::string
        std::cout<<originalWord<<" : "<<newWord<<std::endl;
        original.replace(start_pos, length+1, newWord);
        pos = end_pos + start_tag.size() + end_tag.size(); // CHANGED: Added the size of the two tags
    }
}

更新

在查看pos ， found和start_pos ，似乎其中兩個是多余的。

std::size_t start_pos = 0;
while((start_pos = original.find("\"", start_pos)) != std::string::npos)
{
    std::size_t end_pos = original.find_first_of("\"", start_pos+1);
    if (end_pos == std::string::npos) // If the number of quotation characters is odd you would get undefined behavior
        break;
    std::size_t length = end_pos-start_pos;
    std::string originalWord = original.substr(start_pos+1, length-1);
    std::string newWord = start_tag + "\"" + originalWord + end_tag; // CHANGED: Added the start and end tags as std::string
    std::cout << originalWord << " : " << newWord <<std::endl;
    original.replace(start_pos, length+1, newWord);
    start_pos = end_pos + start_tag.size() + end_tag.size(); // CHANGED: Added the size of the two tags
}

在線嘗試

Answer 3

您應該std::regex

text = std::regex_replace(text,std::regex("string to be replaced"),"string with it earlier should be replaced");