在某些條件下從列表中提取數據

Question

基本上，我試圖添加兩個midi文件，並且互聯網上沒有太多有關此文件的信息，所以我正在嘗試自己的文件。

到目前為止，我所做的是添加了兩個midi消息（midi數據的類型），並且列出了兩個midi消息。 這意味着我現在擁有所有需要合並兩個Midi的數據。 問題是我無法以特定格式添加數據。

所以我的代碼是：

  from mido import MidiFile, MidiTrack

mid = MidiFile('har.mid')
mid2 = MidiFile('har2.mid')

l = [msg for track in mid.tracks for msg in track]
l.pop()
ka = [msg for track in mid2.tracks for msg in track]
ka.pop()

result = l + ka

for messagess in result:
    print(messagess)

我得到這個輸出：

note_on channel=0 note=59 velocity=40 time=0
note_on channel=0 note=60 velocity=40 time=0
note_on channel=0 note=64 velocity=40 time=0
note_off channel=0 note=59 velocity=0 time=55
note_off channel=0 note=64 velocity=0 time=0
note_on channel=0 note=52 velocity=40 time=0
note_off channel=0 note=60 velocity=0 time=55
note_on channel=0 note=64 velocity=40 time=0
note_on channel=0 note=67 velocity=40 time=0
note_off channel=0 note=67 velocity=0 time=55
note_on channel=0 note=57 velocity=40 time=0
note_off channel=0 note=52 velocity=0 time=55
note_off channel=0 note=57 velocity=0 time=0
note_off channel=0 note=64 velocity=0 time=0
note_on channel=0 note=57 velocity=40 time=55
note_off channel=0 note=57 velocity=0 time=55
note_on channel=0 note=64 velocity=40 time=0
note_on channel=0 note=67 velocity=40 time=0
note_off channel=0 note=64 velocity=0 time=55
note_off channel=0 note=67 velocity=0 time=0
note_on channel=0 note=57 velocity=40 time=110
note_on channel=0 note=64 velocity=40 time=0
note_off channel=0 note=57 velocity=0 time=55
note_off channel=0 note=64 velocity=0 time=0
note_on channel=0 note=62 velocity=40 time=0
note_off channel=0 note=62 velocity=0 time=55
note_on channel=0 note=57 velocity=40 time=110
note_on channel=0 note=62 velocity=40 time=0
note_off channel=0 note=57 velocity=0 time=55
note_off channel=0 note=62 velocity=0 time=0
note_on channel=0 note=60 velocity=40 time=0
note_on channel=0 note=62 velocity=40 time=0
note_on channel=0 note=67 velocity=40 time=0
note_on channel=0 note=60 velocity=40 time=55
note_on channel=0 note=64 velocity=40 time=0
note_off channel=0 note=60 velocity=0 time=55
note_off channel=0 note=62 velocity=0 time=0
note_off channel=0 note=64 velocity=0 time=0
note_off channel=0 note=67 velocity=0 time=55
note_on channel=0 note=64 velocity=40 time=0
note_off channel=0 note=64 velocity=0 time=55
note_on channel=0 note=60 velocity=40 time=0
note_off channel=0 note=60 velocity=0 time=55
note_on channel=0 note=62 velocity=40 time=0
note_off channel=0 note=62 velocity=0 time=55
note_on channel=0 note=64 velocity=40 time=0
note_off channel=0 note=64 velocity=0 time=55
note_on channel=0 note=60 velocity=40 time=110
note_on channel=0 note=62 velocity=40 time=0
note_off channel=0 note=60 velocity=0 time=55
note_off channel=0 note=62 velocity=0 time=0
note_on channel=0 note=48 velocity=40 time=110
note_on channel=0 note=62 velocity=40 time=0
note_off channel=0 note=48 velocity=0 time=55
note_off channel=0 note=62 velocity=0 time=0
note_on channel=0 note=57 velocity=40 time=55
note_on channel=0 note=60 velocity=40 time=0

現在可以，但是問題是我可以添加郵件以這種格式進行跟蹤：

from mido import Message, MidiFile, MidiTrack

mid = MidiFile()
track = MidiTrack()
mid.tracks.append(track)

track.append(Message('program_change', program=12, time=0))
track.append(Message('note_on', note=64, velocity=64, time=32))
track.append(Message('note_off', note=64, velocity=127, time=32))

mid.save('new_song.mid')

所以我的問題是如何從這種格式追加每一行：

note_off channel=0 note=62 velocity=0 time=0

此格式

'note_off', note=62, velocity=0, time=0

在track.append(Message())

因為track.append僅支持以下格式方法：

track.append(Message('note_off', note=62, velocity=0, time=0))

提前致謝。

Answer 1

from mido import MidiFile, MidiTrack

mid = MidiFile('har.mid')
mid2 = MidiFile('har2.mid')

l = [msg for track in mid.tracks for msg in track]
l.pop()
ka = [msg for track in mid2.tracks for msg in track]
ka.pop()

result = l + ka

mid3 = MidiFile()
track = MidiTrack()
mid3.tracks.append(track)

for m in result:
    track.append(m)

mid3.save('new_song.mid')

result的對象應該已經是Message對象，因此您無需再次構造它們。 嘗試使用此代碼，如果它不起作用，請復制完整的錯誤消息，您會回來。