[英]How to convert nested dictionary to dataframe?
我有一個嵌套字典。 這是納斯達克的一些數據。 像這樣:
{'CLSN':
Date Open High Low Close Volume Adj Close
2015-12-31 1.92 1.99 1.87 1.92 79600 1.92
2016-01-04 1.93 1.99 1.87 1.93 39700 1.93
2016-01-05 1.89 1.94 1.85 1.90 50200 1.90,
'CCC':
Date Open High Low Close Volume Adj Close
2015-12-31 17.270000 17.389999 17.120001 17.250000 177200 16.965361
2016-01-04 17.000000 17.219999 16.600000 17.180000 371600 16.896516
2016-01-05 17.190001 17.530001 17.059999 17.450001 417500 17.162061,
}
為了幫助您理解,它是值后跟的關鍵 , 值是數據幀 !
在詢問之前,我嘗試了pd.Panel(nas)['CLSN']
,所以我確定它的值是一個數據幀。 但pd.Panel(nas).to_frame().reset_index()
對我沒有幫助! 它輸出一個空的數據框,其中包含數千個用庫存名稱填充的列。
現在很煩,我想要一個像這樣的數據幀:
index Date Open High Low Close Volume Adj Close CLSN 2015-12-31 1.92 1.99 1.87 1.92 79600.0 1.92
CLSN 2016-01-01 NaN NaN NaN NaN NaN NaN
ClSN 2016-01-04 1.93 1.99 1.87 1.93 39700.0 1.93
CCC 2015-12-31 17.270000 17.389999 17.120001 17.250000 177200.0 16.965361
CCC 2016-01-04 17.000000 17.219999 16.600000 17.180000 371600.0 16.896516
CCC 2016-01-05 17.190001 17.530001 17.059999 17.450001 417500.0 17.162061
當然,我可以使用for
循環來獲取每個股票的數據框,但它會讓我加入它們。
你有更好的主意嗎? 非常願意知道!
至MaxU:使用方法print(nas['CLSN'].head())
,輸出如下:
Open High Low Close Volume Adj Close
Date
2015-12-31 1.92 1.99 1.87 1.92 79600 1.92
2016-01-04 1.93 1.99 1.87 1.93 39700 1.93
2016-01-05 1.89 1.94 1.85 1.90 50200 1.90
2016-01-06 1.86 1.89 1.77 1.78 62100 1.78
2016-01-07 1.75 1.80 1.75 1.77 117000 1.77
更新:
假設Date
是索引(不是常規列):
來源字典:
In [70]: d2
Out[70]:
{'CCC': Open High Low Close Volume Adj Close
Date
2015-12-31 17.270000 17.389999 17.120001 17.250000 177200 16.965361
2016-01-04 17.000000 17.219999 16.600000 17.180000 371600 16.896516
2016-01-05 17.190001 17.530001 17.059999 17.450001 417500 17.162061,
'CLSN': Open High Low Close Volume Adj Close
Date
2015-12-31 1.92 1.99 1.87 1.92 79600 1.92
2016-01-04 1.93 1.99 1.87 1.93 39700 1.93
2016-01-05 1.89 1.94 1.85 1.90 50200 1.90}
解:
In [73]: pd.Panel(d2).swapaxes(0, 2).to_frame().reset_index(level=0).sort_index()
Out[73]:
Date Open High Low Close Volume Adj Close
minor
CCC 2015-12-31 17.270000 17.389999 17.120001 17.250000 177200.0 16.965361
CCC 2016-01-04 17.000000 17.219999 16.600000 17.180000 371600.0 16.896516
CCC 2016-01-05 17.190001 17.530001 17.059999 17.450001 417500.0 17.162061
CLSN 2015-12-31 1.920000 1.990000 1.870000 1.920000 79600.0 1.920000
CLSN 2016-01-04 1.930000 1.990000 1.870000 1.930000 39700.0 1.930000
CLSN 2016-01-05 1.890000 1.940000 1.850000 1.900000 50200.0 1.900000
或者,您可以將Date
作為索引的一部分:
In [74]: pd.Panel(d2).swapaxes(0, 2).to_frame().sort_index()
Out[74]:
Open High Low Close Volume Adj Close
Date minor
2015-12-31 CCC 17.270000 17.389999 17.120001 17.250000 177200.0 16.965361
CLSN 1.920000 1.990000 1.870000 1.920000 79600.0 1.920000
2016-01-04 CCC 17.000000 17.219999 16.600000 17.180000 371600.0 16.896516
CLSN 1.930000 1.990000 1.870000 1.930000 39700.0 1.930000
2016-01-05 CCC 17.190001 17.530001 17.059999 17.450001 417500.0 17.162061
CLSN 1.890000 1.940000 1.850000 1.900000 50200.0 1.900000
舊答案 - 它假定Date
是常規列(不是索引)試試這個:
In [59]: pd.Panel(d).swapaxes(0, 2).to_frame().reset_index('major', drop=True).sort_index()
Out[59]:
Date Open High Low Close Volume Adj Close
minor
CCC 2015-12-31 17.27 17.39 17.12 17.25 177200 16.9654
CCC 2016-01-04 17 17.22 16.6 17.18 371600 16.8965
CCC 2016-01-05 17.19 17.53 17.06 17.45 417500 17.1621
CLSN 2015-12-31 1.92 1.99 1.87 1.92 79600 1.92
CLSN 2016-01-04 1.93 1.99 1.87 1.93 39700 1.93
CLSN 2016-01-05 1.89 1.94 1.85 1.9 50200 1.9
其中d
是nested dictionary
:
In [60]: d
Out[60]:
{'CCC': Date Open High Low Close Volume Adj Close
0 2015-12-31 17.270000 17.389999 17.120001 17.250000 177200 16.965361
1 2016-01-04 17.000000 17.219999 16.600000 17.180000 371600 16.896516
2 2016-01-05 17.190001 17.530001 17.059999 17.450001 417500 17.162061,
'CLSN': Date Open High Low Close Volume Adj Close
0 2015-12-31 1.92 1.99 1.87 1.92 79600 1.92
1 2016-01-04 1.93 1.99 1.87 1.93 39700 1.93
2 2016-01-05 1.89 1.94 1.85 1.90 50200 1.90}
也許pandas.concat正是你要找的:
In [8]: data = dict(A=pd.DataFrame([[1,2], [3,4]], columns=['X', 'Y']),
B=pd.DataFrame([[1,2], [3,4]], columns=['X', 'Y']),)
In [9]: data
Out[9]:
{'A': X Y
0 1 2
1 3 4,
'B': X Y
0 1 2
1 3 4}
In [10]: pd.concat(data)
Out[10]:
X Y
A 0 1 2
1 3 4
B 0 1 2
1 3 4
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