[英]How can I output an object as json without the property names?
我有一個帶有一些API的WebAPI 2項目,這些API以Json格式返回數據。 然后,將這些Json文件加載到由單獨的前端開發機構創建的圖形中。 這些圖接受以下格式的Json文件:
"colors": {
"Europe": "red",
"North-America": "blue",
"South-America": "green",
"Asia": "purple",
"Other": "grey"
}
我的WebAPI項目將數據輸出為Json,但是它包含如下屬性名稱:
"colors": [
{
"Title": "Europe",
"ColorName": "red"
},
{
"Title": "North-America",
"ColorName": "blue"
},
{
"Title": "South-America",
"ColorName": "green"
},
{
"Title": "Asia",
"ColorName": "purple"
},
{
"Title": "Other",
"ColorName": "grey"
}
]
有沒有屬性名稱的標准數據輸出方法嗎?
我正在使用標准的WebAPI 2安裝及其所有默認設置,其中包括對Newtonsoft.Json的引用。
如果您使用的是json.net,則一種方法是定義一個自定義JsonConverter
:
public class Color
{
public string Title { get; set; }
public string ColorName { get; set; }
}
public class ColorsConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(Color[]);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var colors = (Color[]) value;
var temp = colors.ToDictionary(x => x.Title, x => x.ColorName);
serializer.Serialize(writer, temp);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
然后使用它:
var colors = new[]
{
new Color {Title = "Europe", ColorName = "red"},
new Color {Title = "North-America", ColorName = "blue"},
new Color {Title = "South-America", ColorName = "green"},
new Color {Title = "Asia", ColorName = "purple"},
new Color {Title = "Other", ColorName = "grey"}
};
var json = JsonConvert.SerializeObject(new {colors}, new ColorsConverter());
這將產生如下的json:
{
"colors": {
"Europe": "red",
"North-America": "blue",
"South-America": "green",
"Asia": "purple",
"Other": "grey"
}
}
如果您將其解碼,則將是相同的,它們都可以被解碼為json對象,這意味着實現並希望對您有所幫助
當您獲得api數據時,就這樣更改...
$(document).ready(function () {
//your api json data
var rootObject = {
"colors": [
{
"Title": "Europe",
"ColorName": "red"
},
{
"Title": "North-America",
"ColorName": "blue"
},
{
"Title": "South-America",
"ColorName": "green"
},
{
"Title": "Asia",
"ColorName": "purple"
},
{
"Title": "Other",
"ColorName": "grey"
}]
}
var jsonArr = [];
for (var i = 0; i < rootObject.colors.length; i++) {
var temp={};
temp[rootObject.colors[i].Title] = rootObject.colors[i].ColorName;
jsonArr.push(temp);
}
var stringJson = JSON.stringify(jsonArr);
alert(stringJson );
});
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