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如何在不使用屬性名稱的情況下將對象輸出為json?

[英]How can I output an object as json without the property names?

我有一個帶有一些API的WebAPI 2項目,這些API以Json格式返回數據。 然后,將這些Json文件加載到由單獨的前端開發機構創建的圖形中。 這些圖接受以下格式的Json文件:

"colors": {
    "Europe": "red",
    "North-America": "blue",
    "South-America": "green",
    "Asia": "purple",
    "Other": "grey"
}

我的WebAPI項目將數據輸出為Json,但是它包含如下屬性名稱:

"colors": [
{
  "Title": "Europe",
  "ColorName": "red"
},
{
  "Title": "North-America",
  "ColorName": "blue"
},
{
  "Title": "South-America",
  "ColorName": "green"
},
{
  "Title": "Asia",
  "ColorName": "purple"
},
{
  "Title": "Other",
  "ColorName": "grey"
}

]

有沒有屬性名稱的標准數據輸出方法嗎?

我正在使用標准的WebAPI 2安裝及其所有默認設置,其中包括對Newtonsoft.Json的引用。

如果您使用的是json.net,則一種方法是定義一個自定義JsonConverter

public class Color
{
    public string Title { get; set; }
    public string ColorName { get; set; }
}

public class ColorsConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Color[]);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var colors = (Color[]) value;

        var temp = colors.ToDictionary(x => x.Title, x => x.ColorName);

        serializer.Serialize(writer, temp);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

然后使用它:

var colors = new[]
{
    new Color {Title = "Europe", ColorName = "red"},
    new Color {Title = "North-America", ColorName = "blue"},
    new Color {Title = "South-America", ColorName = "green"},
    new Color {Title = "Asia", ColorName = "purple"},
    new Color {Title = "Other", ColorName = "grey"}
};

var json = JsonConvert.SerializeObject(new {colors}, new ColorsConverter());

這將產生如下的json:

{
  "colors": {
    "Europe": "red",
    "North-America": "blue",
    "South-America": "green",
    "Asia": "purple",
    "Other": "grey"
  }
}

如果您將其解碼,則將是相同的,它們都可以被解碼為json對象,這意味着實現並希望對您有所幫助

當您獲得api數據時,就這樣更改...

 $(document).ready(function () {

    //your api json data
    var rootObject = {
        "colors": [
{
"Title": "Europe",
"ColorName": "red"
},
{
"Title": "North-America",
"ColorName": "blue"
},
{
"Title": "South-America",
"ColorName": "green"
},
{
"Title": "Asia",
"ColorName": "purple"
},
{
"Title": "Other",
"ColorName": "grey"
}]
    }
    var jsonArr = [];
    for (var i = 0; i < rootObject.colors.length; i++) {
        var temp={};
        temp[rootObject.colors[i].Title] = rootObject.colors[i].ColorName;

        jsonArr.push(temp);
    }

    var stringJson = JSON.stringify(jsonArr);

    alert(stringJson );
    });

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