[英]Newtonsoft.Json Deserialize XmlAnyAttribute?
我有一個類,有一個對象:
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.34283")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=true)]
public partial class Scores : baseModel
{
private System.Xml.XmlAttribute[] anyAttrField;
/// <remarks/>
[System.Xml.Serialization.XmlAnyAttributeAttribute()]
public System.Xml.XmlAttribute[] AnyAttr
{
get
{
return this.anyAttrField;
}
set
{
this.anyAttrField = value;
}
}
}
從父類(其片段):
public parial class LandingPage : baseModel
{
private string projectNameField;
private Scores scoresField;
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string projectName
{
get { return this.projectNameField; }
set { this.projectNameField = value; }
}
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public Scores scores
{
get { return this.scoresField; }
set { this.scoresField = value }
}
}
我正在嘗試使用的JSON字符串:
{
"projectName":"PROJECTTEST",
"scores":{
"browLocker":100,
"heavyAd":0,
"walletRedirection":0
}
}
NewtonSoft.JsonConvert會忽略分數子字段...
我如何輕松地將其轉換為工作方式?
鑒於您的Scores
類型沒有要序列化的屬性,您可以為其創建一個自定義JsonConverter
,它將XmlAttribute []
數組轉換為Dictionary<string, string>
然后序列化該字典以代替Scores
對象:
public class XmlAttributeArrayConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(XmlAttribute[]);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.Null)
return null;
var dict = serializer.Deserialize<Dictionary<string, string>>(reader);
var doc = new XmlDocument();
return dict.Select(p => { var a = doc.CreateAttribute(p.Key); a.Value = p.Value; return a; }).ToArray();
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
// TODO: determine how to represent XmlAttribute values with non-empty NamespaceURI - or throw an exception.
var attributes = (IEnumerable<XmlAttribute>)value;
var dict = attributes.ToDictionary(a => a.Name, a => a.Value);
serializer.Serialize(writer, dict);
}
}
class ScoresConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(Scores);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.Null)
return null;
var attributes = (XmlAttribute[])new XmlAttributeArrayConverter().ReadJson(reader, typeof(XmlAttribute[]), null, serializer);
return new Scores { AnyAttr = attributes };
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var scores = (Scores)value;
if (scores.AnyAttr == null)
writer.WriteNull();
else
{
new XmlAttributeArrayConverter().WriteJson(writer, scores.AnyAttr, serializer);
}
}
}
(請注意,我將一些邏輯提取到了單獨的XmlAttributeArrayConverter
中,以防其他地方使用。)
然后將其應用於“ Scores
,如下所示:
[JsonConverter(typeof(ScoresConverter))]
public partial class Scores
{
}
樣品提琴 。
請注意,如果XML屬性之一恰好位於名稱空間中(大多數情況下都不是 ),則該名稱空間不會被序列化。 如果您的屬性可能具有名稱空間,則需要確定如何將屬性的全名轉換為JSON屬性名。 {namespace}localname
是一種可能,這就是XName.ToString()
所使用的。
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