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Newtonsoft.Json反序列化XmlAnyAttribute嗎?

[英]Newtonsoft.Json Deserialize XmlAnyAttribute?

我有一個類,有一個對象:

[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.34283")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=true)]
public partial class Scores : baseModel
{
   private System.Xml.XmlAttribute[] anyAttrField;
   /// <remarks/>
   [System.Xml.Serialization.XmlAnyAttributeAttribute()]
   public System.Xml.XmlAttribute[] AnyAttr
  {
      get
      {
         return this.anyAttrField;
      }
      set
      {
         this.anyAttrField = value;
      }
   }
}

從父類(其片段):

public parial class LandingPage : baseModel
{
    private string projectNameField;
    private Scores scoresField;
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public string projectName
    {
        get { return this.projectNameField; }
        set { this.projectNameField = value; }
    }
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
    public Scores scores
    {
        get { return this.scoresField; }
        set { this.scoresField = value }
    }
}

我正在嘗試使用的JSON字符串:

{
    "projectName":"PROJECTTEST",
    "scores":{
        "browLocker":100,
        "heavyAd":0,
        "walletRedirection":0
    }
}

NewtonSoft.JsonConvert會忽略分數子字段...

我如何輕松地將其轉換為工作方式?

鑒於您的Scores類型沒有要序列化的屬性,您可以為其創建一個自定義JsonConverter ,它將XmlAttribute []數組轉換為Dictionary<string, string>然后序列化該字典以代替Scores對象:

public class XmlAttributeArrayConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(XmlAttribute[]);
    } 

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType == JsonToken.Null)
            return null;
        var dict = serializer.Deserialize<Dictionary<string, string>>(reader);
        var doc = new XmlDocument();
        return dict.Select(p => { var a = doc.CreateAttribute(p.Key); a.Value = p.Value; return a; }).ToArray();
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        // TODO: determine how to represent XmlAttribute values with non-empty NamespaceURI - or throw an exception.
        var attributes = (IEnumerable<XmlAttribute>)value;
        var dict = attributes.ToDictionary(a => a.Name, a => a.Value);
        serializer.Serialize(writer, dict);
    }
}

class ScoresConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Scores);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType == JsonToken.Null)
            return null;
        var attributes = (XmlAttribute[])new XmlAttributeArrayConverter().ReadJson(reader, typeof(XmlAttribute[]), null, serializer);
        return new Scores { AnyAttr = attributes };
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var scores = (Scores)value;
        if (scores.AnyAttr == null)
            writer.WriteNull();
        else
        {
            new XmlAttributeArrayConverter().WriteJson(writer, scores.AnyAttr, serializer);
        }
    }
}

(請注意,我將一些邏輯提取到了單獨的XmlAttributeArrayConverter中,以防其他地方使用。)

然后將其應用於“ Scores ,如下所示:

[JsonConverter(typeof(ScoresConverter))]
public partial class Scores
{
}

樣品提琴

請注意,如果XML屬性之一恰好位於名稱空間中(大多數情況下都不是 ),則該名稱空間不會被序列化。 如果您的屬性可能具有名稱空間,則需要確定如何將屬性的全名轉換為JSON屬性名。 {namespace}localname是一種可能,這就是XName.ToString()所使用的。

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