尋找連續的數字

Question

好的-所以我在互聯網上搜索了此內容，但我發現的所有示例都與我的完全不同。

我有一個5列和數千行的表。 我需要在每一行中找到連續的數字。 我需要對以下情況進行3個查詢

n1   n2   n3   n4   n5
=======================
 1     3    4    6    9   = should result in 1 (when checking for pairs)
 1     3    4    5    9   = should result in 1 (when checking for triplets)
 1     2    5    8    9   = should result in 1 (when checking for double pairs)

這就是我必須將列移到行中的方法，但是我不確定現在如何檢查。

select n1 from (
select n1 from myTable where Id  = 1
union all select n2 from myTable where Id = 1
union all select n3 from myTable where Id = 1
union all select n4 from myTable where Id = 1
union all select n5 from myTable where Id = 1
) t
order by n1

謝謝你的幫助！

@TimBiegeleise，更新：所以我在谷歌上找到了關於差距和島嶼的信息：

SELECT ID, StartSeqNo=MIN(SeqNo), EndSeqNo=MAX(SeqNo)
FROM (
SELECT ID, SeqNo
    ,rn=SeqNo-ROW_NUMBER() OVER (PARTITION BY ID ORDER BY SeqNo)
FROM dbo.GapsIslands) a
GROUP BY ID, rn;

這是我更新的查詢，將列轉換為行（但是它需要2條語句，我寧願有1條語句）並實現孤島部分-但我不知道該怎么給我所需的結果（見上文）。 下面我顯示原始行數據和結果。

select n1, IDENTITY (INT, 1, 1) AS ID 
into #test
from (
select n1 from myTable where Id  = 8
union all select n2 from myTable where Id = 8
union all select n3 from myTable where Id = 8
union all select n4 from myTable where Id = 8
union all select n5 from myTable where Id = 8
) as t
order by n1

SELECT ID, StartSeqNo=MIN(n1), EndSeqNo=MAX(n1)
FROM (
SELECT ID, n1
    ,rn=n1-ROW_NUMBER() OVER (PARTITION BY ID ORDER BY n1)
FROM #test) a
GROUP BY ID, rn

drop table #test

original row - should return 1 (when checking for "pair"/consecutive numbers
n1   n2   n3   n4   n5
=======================
31   27   28   36   12

我通過上述查詢得到的結果：

    StartSeqNo  EndSeqNo
1   12          12
2   27          27
3   28          28
4   31          31
5   36          36

救命 ：-） ！

Answer 1

好，我知道了。 該查詢為上述行返回值1

select COUNT(*) as pairs 
from (
SELECT StartSeqNo=MIN(n1), EndSeqNo=MAX(n1)
    FROM (
        SELECT n1, rn=n1-ROW_NUMBER() OVER (ORDER BY n1)
            from (
                select n1 from myTable where Id  = 8
                union all select n2 from myTable where Id = 8
                union all select n3 from myTable where Id = 8
                union all select n4 from myTable where Id = 8
                union all select n5 from myTable where Id = 8
            ) t
    ) x
GROUP BY rn
) z
where StartSeqNo+1 = EndSeqNo