如何在沒有依賴類的情況下將C＃中的Json轉換為List

Question

我需要將Json序列化為值列表，並且不希望有任何依賴類（意味着get，set），因為動態更改了Json密鑰，並且在執行后還增加了數千個密鑰（我有一個外部json文件）。

我搜索了很多鏈接，但無法解決問題，我只獲得了轉換后的字典類型。 示例json在下面，

{"ALC":"FSC","AVS":"7","CAB":"M","CL":"W","CNF":"N","CNX":"N","DES":"DEL","DTE":"3","EDT":"29 Jun 2017 09:20","FBAG":"15 Kg","FBC":"W2IPO","FCUR":null,"FN":"9W 822","FQT":true,"FRI":"FSC0","FYT":"160","ITN":"0","JYT":"160","MCL":"0","OFF":0,"OFI":false,"OFR":null,"ORG":"MAA","PC":"9W","RBD":null,"RFN":"False","RTK":"TAX:1801ASPLIT2901ASPLIT1101ASPLITADT1ASPLIT","SDT":"29 Jun 2017 06:40","SGD":"Aircraft Type : 738\u000d\u000aJourney Time : 160\u000d\u000aStart Terminal : 1\u000d\u000aEndTerminal : 3\u000d\u000aBaggage : 15 Kg","SGR":"","STE":"1","STP":"0","TNF":false,"VIA":"","VIAITN":null}

我在此問題上停留了一天，請任何人提供解決方案。我的代碼如下。

  var json = File.ReadAllText(Server.MapPath("JSON/Flight_res.txt"));
  JToken rss = JObject.Parse(json);
  var items= rss.SelectToken("FL").ToString();
  var jss = new JavaScriptSerializer();

  dynamic listofobj = jss.Deserialize<dynamic>(items.ToString());

Answer 1

JSON.net允許您按以下說明反序列化為匿名類型： http : //www.newtonsoft.com/json/help/html/DeserializeAnonymousType.htm

所以你可以用這種方式

string json = "{\"ALC\":\"FSC\",\"AVS\":\"7\",\"CAB\":\"M\",\"CL\":\"W\",\"CNF\":\"N\",\"CNX\":\"N\",\"DES\":\"DEL\",\"DTE\":\"3\",\"EDT\":\"29 Jun 2017 09:20\",\"FBAG\":\"15 Kg\",\"FBC\":\"W2IPO\",\"FCUR\":null,\"FN\":\"9W 822\",\"FQT\":true,\"FRI\":\"FSC0\",\"FYT\":\"160\",\"ITN\":\"0\",\"JYT\":\"160\",\"MCL\":\"0\",\"OFF\":0,\"OFI\":false,\"OFR\":null,\"ORG\":\"MAA\",\"PC\":\"9W\",\"RBD\":null,\"RFN\":\"False\",\"RTK\":\"TAX:1801ASPLIT2901ASPLIT1101ASPLITADT1ASPLIT\",\"SDT\":\"29 Jun 2017 06:40\",\"SGD\":\"Aircraft Type : 738\u000d\u000aJourney Time : 160\u000d\u000aStart Terminal : 1\u000d\u000aEndTerminal : 3\u000d\u000aBaggage : 15 Kg\",\"SGR\":\"\",\"STE\":\"1\",\"STP\":\"0\",\"TNF\":false,\"VIA\":\"\",\"VIAITN\":null}";

dynamic myData = JsonConvert.DeserializeAnonymousType(json, new ExpandoObject());

ExpandoObject實際上只是內部的一種特殊類型的字典，因此您可以通過這樣迭代來提取數據；

foreach (var property in (IDictionary<string, string>)myData)
{
    Console.WriteLine(property.Key + ": " + property.Value);    
}

或者，如果您知道諸如以下代碼中的“鍵”，則可以確切指定要提取的內容

string text = myData.ALC;

但是，因為ExpandoObject只是字典的一種，所以這與通過執行以下操作直接提取到字典沒有什么不同；

Dictionary<string, Object> myDict = JsonConvert.DeserializeObject<Dictionary<string, string>>(json);
foreach (var property in (IDictionary<String, string>)myDict)
{
    Console.WriteLine(property.Key + ": " + property.Value);
}

Answer 2

您可以將其轉換為字典。

using Newtonsoft.Json;

string jsonString = "{\"ALC\":\"FSC\",\"AVS\":\"7\",\"CAB\":\"M\",\"CL\":\"W\",\"CNF\":\"N\",\"CNX\":\"N\",\"DES\":\"DEL\",\"DTE\":\"3\",\"EDT\":\"29 Jun 2017 09:20\",\"FBAG\":\"15 Kg\",\"FBC\":\"W2IPO\",\"FCUR\":null,\"FN\":\"9W 822\",\"FQT\":true,\"FRI\":\"FSC0\",\"FYT\":\"160\",\"ITN\":\"0\",\"JYT\":\"160\",\"MCL\":\"0\",\"OFF\":0,\"OFI\":false,\"OFR\":null,\"ORG\":\"MAA\",\"PC\":\"9W\",\"RBD\":null,\"RFN\":\"False\",\"RTK\":\"TAX:1801ASPLIT2901ASPLIT1101ASPLITADT1ASPLIT\",\"SDT\":\"29 Jun 2017 06:40\",\"SGD\":\"Aircraft Type : 738\u000d\u000aJourney Time : 160\u000d\u000aStart Terminal : 1\u000d\u000aEndTerminal : 3\u000d\u000aBaggage : 15 Kg\",\"SGR\":\"\",\"STE\":\"1\",\"STP\":\"0\",\"TNF\":false,\"VIA\":\"\",\"VIAITN\":null}";

Dictionary<string, string> dict = new Dictionary<string, string>();

dict = JsonConvert.DeserializeObject <Dictionary<string, string>>(jsonString);
var list = dict.ToList(); 

編輯

var json = File.ReadAllText("Demo.json");

Dictionary<string, string> dict = new Dictionary<string, string>();

dict = JsonConvert.DeserializeObject<Dictionary<string, string>>(json);

var list = dict.ToList();

這段代碼工作正常。