從正則表達式創建所有組合

Question

我有一些句子定義了隨機組合的模板：

I like dogs/cats    
I want to eat today/(the next day)

我嘗試使用正則表達式：

m = re.search(r'(?P<list>[A-Za-z]+/([A-Za-z]+)+)', sentence)
words = m.group('list').split('/')
combs = [comb for comb in [sentence.replace(m.group('list'), w) for w in words]]

對於第一句話，我想要的是['i like dogs', 'i like cats'] 。 對於第二句話， re.search返回None 。 我想要得到的是['I want to eat today', 'I want to eat the next day'] 。

我該如何更改正則表達式？

Answer 1

（我今天想吃）* |（第二天）

正則表達式將選擇您想要的文本...

Answer 2

r'(?P<list>[A-Za-z]+/([a-zA-Z]+|\\(.+?\\)))''

([a-zA-Z]+|\\(.+?\\))匹配字符串，例如“單詞”或“（某些單詞）”。 並且它也匹配“（）”，我們需要使用strip刪除標題“（”和尾隨“）”。

m = re.search(r'(?P<list>[A-Za-z]+/([a-zA-Z]+|\(.+?\)))', sentence)
words = m.group('list').split('/')
combs = [comb for comb in [sentence.replace(m.group('list'), w.strip('()')) for w in words]]

Answer 3

使用以下代碼，您將獲得類似

> sentence = 'I want to eat today/(the next day)' m =
> re.search(r'(?P<list>[A-Za-z]+/([A-Za-z]+|(\(.*?\))))', sentence)
> print m.group('list') words = m.group('list').split('/') combs = [comb
> for comb in [sentence.replace(m.group('list'), w) for w in words]]
> print combs

['I want to eat today', 'I want to eat (the next day)'

您可以進行額外的圓頂處理以消除多余的括號，這應該很容易