[英]Create all combinations from regex
我有一些句子定义了随机组合的模板:
I like dogs/cats
I want to eat today/(the next day)
我尝试使用正则表达式:
m = re.search(r'(?P<list>[A-Za-z]+/([A-Za-z]+)+)', sentence)
words = m.group('list').split('/')
combs = [comb for comb in [sentence.replace(m.group('list'), w) for w in words]]
对于第一句话,我想要的是['i like dogs', 'i like cats']
。 对于第二句话, re.search
返回None
。 我想要得到的是['I want to eat today', 'I want to eat the next day']
。
我该如何更改正则表达式?
(我今天想吃)* |(第二天)
正则表达式将选择您想要的文本...
r'(?P<list>[A-Za-z]+/([a-zA-Z]+|\\(.+?\\)))''
([a-zA-Z]+|\\(.+?\\))
匹配字符串,例如“单词”或“(某些单词)”。 并且它也匹配“()”,我们需要使用strip
删除标题“(”和尾随“)”。
m = re.search(r'(?P<list>[A-Za-z]+/([a-zA-Z]+|\(.+?\)))', sentence)
words = m.group('list').split('/')
combs = [comb for comb in [sentence.replace(m.group('list'), w.strip('()')) for w in words]]
使用以下代码,您将获得类似
> sentence = 'I want to eat today/(the next day)' m =
> re.search(r'(?P<list>[A-Za-z]+/([A-Za-z]+|(\(.*?\))))', sentence)
> print m.group('list') words = m.group('list').split('/') combs = [comb
> for comb in [sentence.replace(m.group('list'), w) for w in words]]
> print combs
['I want to eat today', 'I want to eat (the next day)'
您可以进行额外的圆顶处理以消除多余的括号,这应该很容易
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