[英]Set a default on my dictonary python
問題我只想從數據庫中獲取view_id列,但是我想要第一個鍵的序列號。 以下是我到目前為止所能提供的幫助!
如果我嘗試將count設置為第一個鍵,這將給我帶來語法錯誤:
import pyodbc
class ShopView(object):
def getViews(self):
conn = pyodbc.connect(r'DSN=mydb;UID=test;PWD=xxxxxxxxxxxxx')
sql = "SELECT DISTINCT view_id FROM [TEST].[dbo].[SHOP_VIEW]"
cursor = conn.cursor()
cursor.execute(sql)
count = 0
try:
return {'shop_views':
[dict(zip(count += 1, [column[0] for column in cursor.description], row))
for row in cursor.fetchall()]}
finally:
cursor.close()
conn.close()
我也嘗試過此方法,但遇到一個新錯誤: ValueError: dictionary update sequence element #0 has length 3; 2 is required
ValueError: dictionary update sequence element #0 has length 3; 2 is required
try:
return {'shop_views':
[dict(zip([data[0] for data in str(cursor.rowcount)], [column[0] for column in cursor.description], row))
for row in cursor.fetchall()]}
finally:
cursor.close()
conn.close()
這是現在的樣子
{'shop_views': [{'view_id': 'ACTOB'}, {'view_id': 'BANDDIES'}, {'view_id': 'SpareNCLathe'}]}
這是我想要的樣子:
{'shop_views': [{'count': '1', 'view_id': 'ACTOB'}{'count': '2', 'view_id': 'BANDDIES'}, {'count': '3', 'view_id': 'SpareNCLathe'}]}
未經測試(不適合您的數據庫和連接器),但這是:
[dict(count=str(index), view_id=row[0]) for index, row in enumerate(cursor, 1)]
應該符合您的預期結果。
從文檔:
class enumerate(object)
| enumerate(iterable[, start]) -> iterator for index, value of iterable
|
| Return an enumerate object. iterable must be another object that supports
| iteration. The enumerate object yields pairs containing a count (from
| start, which defaults to zero) and a value yielded by the iterable argument.
| enumerate is useful for obtaining an indexed list:
| (0, seq[0]), (1, seq[1]), (2, seq[2]), ...
請注意,我直接傳遞了cursor
,在大多數db-api實現中,游標本身都是可迭代的-一個懶惰的游標,因此您可以避免只在內存中加載整個結果集( .fetchall()
會發生這種情況)想遍歷它。 如果收到TypeError: XXX object is not iterable
異常,則傳遞cursor.fetchall()
而不是cursor
(並與pyodbc維護人員聯系,要求他們使cursor
變為可迭代)。
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