[英]Filter data from array of Dictionary using predicate iOS SDK
大家好,我有一個字典數組,你能告訴我如何根據字典鍵過濾這些數據。
(
{
"mall_id" = M0550;
"mall_name" = "Amrita Shopping Complex";
},
{
"mall_id" = M0509;
"mall_name" = "Ashoka Market";
},
{
"mall_id" = M0943;
"mall_name" = "Biju Pattnaik Commercial Complex";
},
{
"mall_id" = M0457;
"mall_name" = "BMC Bhawani Mall";
},
{
"mall_id" = M0460;
"mall_name" = "BMC Keshari Mall";
},
{
"mall_id" = M0571;
"mall_name" = "BMC Market Complex";
},
{
"mall_id" = M0453;
"mall_name" = "Forum Mart";
},
{
"mall_id" = M0609;
"mall_name" = "Indradhanu Market";
},
{
"mall_id" = M0558;
"mall_name" = "Kalyani Plaza Market Complex";
},
{
"mall_id" = M0463;
"mall_name" = "Maa Barabhuja Mall";
},
{
"mall_id" = M0553;
"mall_name" = "Mahaveer Complex";
},
{
"mall_id" = M0570;
"mall_name" = "Market Building";
},
{
"mall_id" = M0452;
"mall_name" = "Pal Heights Mall";
},
{
"mall_id" = M0466;
"mall_name" = "Priyadarshini Market Complex";
},
{
"mall_id" = M0677;
"mall_name" = "Ruchika Market";
},
{
"mall_id" = M0504;
"mall_name" = "Shubham Market Complex";
},
{
"mall_id" = M0564;
"mall_name" = "Subhadra Complex";
},
{
"mall_id" = M0559;
"mall_name" = "Sultania Shopping Complex";
},
{
"mall_id" = M0552;
"mall_name" = "Tathastu Complex";
},
{
"mall_id" = M0568;
"mall_name" = "Western Tower Market Building";
}
)
我想要實現的,每當我在搜索欄中輸入任何內容時,它將檢查mall_name鍵並返回數組中的匹配值。
感謝致敬
這將為您提供所需的輸出
目標 - C.
NSArray *filteredData = [yourArrayContainingDictionary filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]];
迅速
let filteredData = yourArrayContainingDictionary.filter{
let string = $0["mall_name"] as! String
return string.hasPrefix("searchText")
}
希望這可以幫助你:)
試試這個吧。 (謂詞就像SQL查詢一樣)
對象C.
NSArray *filterArray = [sourceArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]];
迅速
var filterArray: [Any] = sourceArray.filter { NSPredicate(format: "(mall_name contains[c] %@)", searchText).evaluate(with: $0) }
它將返回其名稱包含搜索字符串的條目。
使用此解決方案
NSArray *filtered = [yourArrayOfDictionary filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", <your search text from search bar>]];
NSArray *filtered = [arrName filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name == %@)", requiredMailName]];
NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", wantedMallID]];
這是我使用謂詞和經典版本的2個版本:
let dict = [
[
"mall_id": 1,
"mall_name": "Amrita Shopping Complex"
],
[
"mall_id": 2,
"mall_name": "Ashoka Market"
] ]
// Example using Predicate
let mallNamePredicate = NSPredicate(format: "mall_name contains %@", "Ashoka")
let filteredWithPredicate = (dict as NSArray).filtered(using: mallNamePredicate)
// Classical filter example
let filtered = dict.filter { pair in
guard let mallName = pair["mall_name"] as? String else { return false }
return mallName.hasPrefix("Ashoka")
}
這種方式更加流暢
let mallArray = [
[
"mall_id": "M0550",
"mall_name": "Amrita Shopping Complex"
],
[
"mall_id": "M0509",
"mall_name": "Ashoka Market"
]
]
func isMatching(_ searchText: String) -> [[String: Any]] {
let filteredArray = mallArray.filter {
return $0["mall_name"]!.contains(searchText)
}
return filteredArray
}
let malls = isMatching("Ashoka")
print(malls)
這為您提供了一系列僅包含requiredMallID
的詞典
NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", requiredMallID]];
例如,
NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", "M0550"]];
給你
(
{
"mall_id" = M0550;
"mall_name" = "Amrita Shopping Complex";
}
)
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