使用謂詞的字典過濾器數組-swift3

Question

我有很多字典。

>[{"name": "John",
"address": 
{"home": "addr1", 
"work": "add2"}
},
{"name": "Anu",
"address": {"home": "addr1", 
"work": "add2"}
}]

我將其保存為這樣的用戶默認值-

let personData1 = [“ name”：“ John”，“ address”：{“ home”：“ addr1”，“ work”：“ add2”}] as [String：Any] let personData2 = [“ name”：“ Anu “，” address“：{” home“：” addr1“，” work“：” add2“}] as [String：Any]

var persons = [personsData, personsData1]
UserDefaults.standard.set(forKey: "persons") 

用另一種方法檢索它，並根據名稱對其進行過濾。 讓名字=“ 約翰 ”

低於錯誤

無法使用類型為（（（Any？）-> Bool）'的參數列表調用'filter'

這是代碼：-

func test () {

    let personData1 = ["name": "John", "addresses": ["home":"addr1", "work": "addr2"]] as [String : Any]
    let personData2 = ["name": "And", "addresses":  ["home":"addr1", "work": "addr2"]] as [String : Any]

    let persons = [personData1, personData2]
    (UserDefaults.standard.set(persons, forKey: "persons")

    print("Saved ----\(UserDefaults.standard.value(forKey: "persons"))")

    if let savedPersons = UserDefaults.standard.value(forKey: "persons") {
        let namePredicate = NSPredicate(format: "name like %@", name);

        var filteredArray: [[String:Any]] = savedPersons.filter { namePredicate.evaluate(with: $0) }

        print("names = \(filteredArray)")
    }
}

如果我嘗試這樣過濾-

let filteredArray = savedBrs.filter { $0["name"] == name }

得到不同的錯誤-

類型“任何”的值沒有成員“過濾器”

Answer 1

使用NSPredicate

let arr = [["name":"Rego","address":["one":"peek","two":"geelo"]],["name":"pppp","address":["one":"peek","two":"geelo"]]]

let neededName = "Rego"

let pre = NSPredicate(format: "name == %@",neededName)

let result = arr.filter { pre.evaluate(with:$0) } 

print(result)

沒有NSPredicate

let result = arr.filter { $0["name"] as? String  == neededName }