熊貓合並具有相同結構的兩個數據框

Question

假設我有兩個數據框：

    x1  x2  x3  
y1  a1  a1  a1      
y2  b1  b1  b1     
y3  c1  c1  c1  

    x1  x2  x3  
y1  a2  a2  a2      
y2  b2  b2  b2     
y3  c2  c2  c2         

哪一個最簡單的方法是從原始數據幀中的同一位置獲取每個元素具有兩個值的列表的以下數據幀？

    x1        x2       x3  
y1  [a1,a2]  [a1,a2]  [a1,a2]     
y2  [b1,b2]  [b1,b2]  [b1,b2]     
y3  [c1,c2]  [c1,c2]  [c1,c2]   

Answer 1

一種（眾多）可能的解決方案：

In [63]: d1.astype(str).add(',').add(d2.astype(str)).apply(lambda x: x.str.split(','))
Out[63]:
          x1        x2        x3
y1  [a1, a2]  [a1, a2]  [a1, a2]
y2  [b1, b2]  [b1, b2]  [b1, b2]
y3  [c1, c2]  [c1, c2]  [c1, c2]

Answer 2

使用applymap

In [953]: df1.applymap(lambda x: [x]) + df2.applymap(lambda x: [x])
Out[953]:
          x1        x2        x3
y1  [a1, a2]  [a1, a2]  [a1, a2]
y2  [b1, b2]  [b1, b2]  [b1, b2]
y3  [c1, c2]  [c1, c2]  [c1, c2]