將過濾器結果合並為循環

Question

我正在使用Django建立一個網站。 我想結合多個過濾結果（Querysets）。

我模特的關系

'工作人員'1：m'會員'1：m'PaymentHistory'1：1'RefundHistory'

我的view.py：

wanted_refund = set()
for m in staff.members.all():
    payment = m.PaymentHistory.filter(division="Membership")
    for p in payment:
        try:
            refund = RefundHistory.objects.filter(payment=p).filter(refund_date__range=[this_month_start, date])

            wanted_refund.add(refund)
        except RefundHistory.DoesNotExist:
            pass
 context = {
             'wanted_refund' : wanted_refund,}
    return render(request, 'refund.html', context)

但是，使用過濾器不起作用。 它只適用於我使用'get'。

print(refund)顯示結果如下：

 < QuerySet [] >

 < QuerySet [] >

 < QuerySet [] >

 < QuerySet [< RefundHistory: RefundHistory object >] >

我想只使用具有該對象的Querysets，我想要的是模板中的下面一個：

{% for refund in wanted_history %}
 {{ refund.refund_date }}
 {{ refund.refund_amount}}
 {% endfor %}

如何將多個過濾器結果傳遞給for循環？

Answer 1

您可以使用管道運算符連接查詢集：

wanted_refund = RefundHistory.objects.none()
for m in staff.members.all():
    payment = m.PaymentHistory.filter(division="Membership")
    for p in payment:
        try:
            wanted_refund |= RefundHistory.objects.filter(payment=p).filter(refund_date__range=[this_month_start, date])
        except RefundHistory.DoesNotExist:
            pass
wanted_refund = wanted_refund.distinct()
context = {'wanted_refund': wanted_refund}
return render(request, 'refund.html', context)

此外，如果它適合您，您可以使用wanted_refund.update(list(refund))代替wanted_refund.add(refund)

Answer 2

使用RefundHistory的單個查詢， RefundHistory每個會員的每次付款的退款歷史記錄：

payments = []
for m in staff.members.all():
    payments.extend(m.PaymentHistory.filter(division="Membership").values_list('pk', flat=True))

wanted_refund = RefundHistory.objects.filter(payment__pk__in=payments, refund_date__range=[this_month_start, date])

context = {'wanted_refund' : wanted_refund,}
return render(request, 'refund.html', context)