如何使用python將txt文件導出到csv中？

Question

我有這樣格式的txt文件：

Monday, Jul 24
8:45 apple 1    
school
ball
dog
8:50 poirot 2   
rouge
chien   
chat
8:55 football 3
asroma
juventus  
inter

如何忽略第一行（星期一，7月24日）並將這些值放入csv，並在每行中插入實際日期？ 我需要這種格式：

A1 Monday, Jul 24
B1:8:45 apple 1   B2:school B3:ball    B4:dog    B5:ACTUALLY DATE
C1:8:50 poirot 2  C2:rouge  C3:chien   C4:chat   C5:ACTUALLY DATE
etcetc..

所以我想以這種格式放置它們。 這是我的實際代碼：

import urllib2
import unicodecsv as csv
import os
import sys
import io
import time
import datetime
import pandas as pd
from bs4 import BeautifulSoup
import sys
import re

#def to_2d(l,n):
#    return [l[i:i+n] for i in range(0, len(l), n)]

with open('air.txt', 'r') as f:
    x = f.read()
print x

req_text = x.split('Test')[1: -1]

data = []
for text in req_text:
    text = text.split('\n', 1)[1]
    for line in text.strip().splitlines():
        data.append([line])

#maindatatable = to_2d(data, 4)

with open('output.csv', "wb") as f:
    output = csv.writer(f, delimiter=';',quotechar = '"', quoting=csv.QUOTE_NONNUMERIC, encoding='latin-1')
    output.writerows(data)

f.close()

我嘗試了to_2d（l，n），但是它不起作用，我知道如何在實際日期中達到這種格式？ [Python 2.7]

更新的代碼，仍然無法正常工作：

 import urllib2 import unicodecsv as csv import os import sys import io import time import datetime import pandas as pd from bs4 import BeautifulSoup import sys import re def to_2d(l,n): return [l[i:i+n] for i in range(0, len(l), n)] with open('air.txt', 'r') as f: x = f.read() print x req_text = x.split('Load')[1: -1] data = [] for text in req_text: text = text.split('\\n', 1)[1] for line in text.strip().splitlines(): data.append([line]) #maindatatable = to_2d(data, 4) from string import ascii_uppercase as LETTERS with open('air.txt') as f, open('output.csv', 'wb') as g: actual_date = f.readline().strip() while True: first_line = f.readline().strip() if not first_line: break second_line = f.readline().strip() third_line = f.readline().strip() fourth_line = f.readline().strip() the_time, noun, number = first_line.split(' ') number = int(number) letter = LETTERS[number] new_line = '%s1:%s %s %s %s2:%s %s3:%s %s4:%s %s5:%s' % (letter, the_time, noun, number, letter, second_line, letter, third_line, letter, fourth_line, letter, actual_date) print (new_line) f.close() 

Answer 1

該腳本僅打印輸出行，而不是將它們寫入輸出csv文件。 但是，這對您來說很容易修改。 還要注意（a）用這種方式最多可以寫25行，因為從'B'到'Z'只有25個字母； （b）如果您的示例輸出文件中的第一行要寫入到csv文件中，那么這將不是對熊貓的有效輸入。

該腳本通過讀取第一行並將其內容actual_date為actual_date以便在輸出行中使用來工作。 然后，它一次讀取四行，以用於創建單個輸出行。

>>> from string import ascii_uppercase as LETTERS
>>> with open('air.txt') as f, open('output.csv', 'wb') as g:
...     actual_date = f.readline().strip()
...     while True:
...         first_line = f.readline().strip()
...         if not first_line: 
...             break
...         second_line = f.readline().strip()
...         third_line = f.readline().strip()
...         fourth_line = f.readline().strip()
...         try:
...             the_time, noun, number = first_line.split(' ')
...         except:
...             print ('invalid input: ', first_line)
...             quit(2)
...         number = int(number)
...         letter = LETTERS[number]
...         new_line = '%s1:%s %s %s %s2:%s %s3:%s %s4:%s %s5:%s' % (letter, the_time, noun, number, letter, second_line, letter, third_line, letter, fourth_line, letter, actual_date)
...         print (new_line)
...         
B1:8:45 apple 1 B2:school B3:ball B4:dog B5:Monday, Jul 24
C1:8:50 poirot 2 C2:rouge C3:chien C4:chat C5:Monday, Jul 24
D1:8:55 football 3 D2:asroma D3:juventus D4:inter D5:Monday, Jul 24