分隔第一個中間姓氏 C#

Question

目標：在用戶輸入姓名時解析姓名，並顯示帶有第一個中間名和姓氏的消息框。 現在它只在你輸入三個名字時才有效，如果你嘗試兩個它會崩潰，我確定這是我的數組的原因，但我不確定我錯在哪里。 超級新手，我自己學習，所以任何幫助將不勝感激！！

用戶看到的 PS GUI 只是一個輸入塊，供他們將他們的名字輸入一行，每個單詞之間有間距。

 private void btnParseName_Click(object sender, System.EventArgs e)
    {
        string fullName = txtFullName.Text;
        fullName = fullName.Trim();

        string[] names = fullName.Split(' ');

        string firstName = "";
        string firstLetter = "";
        string otherFirstLetters = "";
        if (names[0].Length > 0)
        {
            firstName = names[0];
            firstLetter = firstName.Substring(0, 1).ToUpper();
            otherFirstLetters = firstName.Substring(1).ToLower();
        }

        string secondName = "";
        string secondFirstLetter = "";
        string secondOtherLetters = "";
        if (names[1].Length > 0)
         {
            secondName = names[1];
            secondFirstLetter = secondName.Substring(0, 1).ToUpper();
            secondOtherLetters = secondName.Substring(0).ToLower();
         }

        string thirdName = "";
        string thirdFirstLetter = "";
        string thirdOtherLetters = "";
        if (names[2].Length > 0)
        {

            thirdName = names[2];
            thirdFirstLetter = thirdName.Substring(0, 1).ToUpper();
            thirdOtherLetters = thirdName.Substring(0).ToLower();

        }

        MessageBox.Show(
                "First Name:         " + firstLetter + otherFirstLetters + "\n\n" +
                "Middle Name:        " + secondFirstLetter + secondOtherLetters + "\n\n" +
                "Last Name:          " + thirdFirstLetter + thirdOtherLetters);

Answer 1

以下是如何執行此操作的工作示例：

public class FullName
{
    public  string FirstName { get; set; }
    public  string MiddleName { get; set; }
    public  string LastName { get; set; }

    public FullName()
    {

    }

    public FullName(string fullName)
    {
        var nameParts = fullName.Split(new [] {' '}, StringSplitOptions.RemoveEmptyEntries);

        if (nameParts == null)
        {
            return;
        }
        if (nameParts.Length > 0)
        {
            FirstName = nameParts[0];
        }
        if (nameParts.Length > 1)
        {
            MiddleName = nameParts[1];
        }
        if (nameParts.Length > 2)
        {
            LastName = nameParts[2];
        }
    }

    public override string ToString()
    {
        return $"{FirstName} {MiddleName} {LastName}".TrimEnd();
    }
}

用法示例：

class Program
{
    static void Main(string[] args)
    {
        var fullName = new FullName("first middle last");
        Console.WriteLine(fullName);
        Console.ReadLine();
    }
}

Answer 2

您需要檢查並處理第二個名稱為空。 初始化字符串將防止崩潰，然后檢查輸入。

string secondName = "";    
string secondFirstLetter = ""; 
string secondOtherLetters = "";

if(names.Length > 2)
{
    secondName = names[1];
    secondFirstLetter = secondName.Substring(0, 1).ToUpper();
    secondOtherLetters = secondName.Substring(0).ToLower();
}

實際上，值得初始化所有變量或管理用戶輸入驗證。

Answer 3

如另一個答案所述，只有在存在第三個名稱時才需要指定中間名。
下面的方法使用Dictionary.TryGetValue方法和C＃7功能out參數。

var textInfo = System.Globalization.CultureInfo.CurrentCulture.TextInfo;
var names = fullName.Split(' ')
                    .Where(name => string.IsNullOrWhiteSpace(name) == false)
                    .Select(textInfo.ToTitleCase)
                    .Select((Name, Index) => new { Name, Index })
                    .ToDictionary(item => item.Index, item => item.Name);

names.TryGetValue(0, out string firstName);
names.TryGetValue(1, out string middleName);
if (names.TryGetValue(2, out string lastName) == false)
{
    lastName = middleName;
    middleName = null;
}

// Display result
var result = new StringBuilder();
result.AppendLine("First name: ${firstName}");
result.AppendLine("Middle name: ${middleName}");
result.AppendLine("Last name: ${lastName}");

MessageBox.Show(result.ToString());

Answer 4

我知道你的問題已得到解答，你可以通過很多方式來處理這個問題，但這是我的建議，並在此過程中給出了一些解釋：

private void button1_Click(object sender, EventArgs e)
{
    string fullName = "Jean Claude Van Dam";
    fullName = fullName.Trim();

    // So we split it down into tokens, using " " as the delimiter
    string[] names = fullName.Split(' ');

    string strFormattedMessage = "";

    // How many tokens?
    int iNumTokens = names.Length;

    // Iterate tokens
    for(int iToken = 0; iToken < iNumTokens; iToken++)
    {
        // We know the token will be at least one letter
        strFormattedMessage += Char.ToUpper(names[iToken][0]);

        // We can't assume there is more letters (they might have used an initial)
        if(names[iToken].Length > 1)
        {
            // Add them (make it lowercase)
            strFormattedMessage += names[iToken].Substring(1).ToLower();

            // Don't need to add "\n\n" for the last token
            if(iToken < iNumTokens-1)
                strFormattedMessage += "\n\n";
        }

        // Note, this does not take in to account names with hyphens or names like McDonald. They would need further examination.
    }

    if(strFormattedMessage != "")
    {
        MessageBox.Show(strFormattedMessage);
    }
}

這個例子避免了所有的變量。 它利用了運算符[] 。

希望這對你有幫助...... :)

Answer 5

 public static string getMiddleName(string fullName)
    {
        var names = fullName.Split(' ');
        string firstName = names[0];
        string middleName = "";// names[1];
        var index = 0;
        foreach (var item in names)
        {
            if (index > 0 && names.Length -1 < index)
            {
                middleName += item + " ";
            }
            index++;
        }
        return middleName;
    }