[英]Unable to convert an rdd with zipWithIndex to a dataframe in spark
[英]zipWithIndex rdd with initial value
我有一個這樣的RDD:
+----------+--------+
|firstName |lastName|
+----------+--------+
| john| smith|
| anna| tourde|
+----------+--------+
我會像創建zipWithIndex一樣創建一個新列,但給定和初始值為8。
+----------+--------+-----+
|firstName |lastName|index|
+----------+--------+-----+
| john| smith| 8|
| anna| tourde| 9|
+----------+--------+-----+
你有什么主意嗎? 謝謝
rdd.zipWithIndex().map { case (v, ind) =>
(v, ind + 8)
}
使用zipWithIndex
並轉換回數據zipWithIndex
,如下所示
val df1 = spark.sqlContext.createDataFrame(
df.rdd.zipWithIndex.map {
case (row, index) => Row.fromSeq(row.toSeq :+ index + 8)
},
// Create schema for index column
StructType(df.schema.fields :+ StructField("index", LongType, false)))
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