[英]python iterate over a list and remove any duplicates found within lists inside a dictionary and remove the duplicates
我有一個數字列表和一個帶有名稱(鍵)和數字(值)的字典,我需要遍歷名為lotto的列表,然后對照字典中名稱的值檢查它們,如果我找到匹配項,則刪除該列表字典值中的數字。
這是我到目前為止的東西,但它只是打印出原始的字典鍵和值
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]
for i in players.values():
if i in lotto:
players.values.remove(i)
print (players)
任何幫助
您以錯誤的方式訪問dict值。 看一下以下內容:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]
for p, val in players.items():
for num in lotto:
if num in val:
players[p].remove(num)
print (players) # {'al': [8, 9], 'ray': [7, 8]}
如果列表值中的項目順序對您而言並不重要,則可以使用以下更快的變體:
players = {'ray': [1,2,3,6,7,8], 'al':[1,2,3,4,8,9]}
lotto = [1,2,3,4,5,6]
lotto = set(lotto)
for p, val in players.items():
players[p] = list(set(val) - lotto)
print (players) # {'ray': [8, 7], 'al': [8, 9]}
也可以在以下單行代碼中進行壓縮(盡管它可以重新創建dict
而不是對其進行修改):
players = {k: list(set(val) - lotto) for k, v in players.items()}
您的問題是您試圖從錯誤的列表中刪除號碼。 players.values
是每個鍵的值的列表,而不是每個鍵的單個值的列表 。 使用每個鍵的單獨值:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto = [1,2,3,4,5,6,]
for key, value in players.items():
for i in lotto:
if i in value:
value.remove(i)
print(players)
然后可以通過使用字典理解來縮短:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]
players = {k: list(set(v) - set(lotto)) for k, v in players.items()}
print(players) # {'ray': [8, 7], 'al': [8, 9]}
另外,如果程序中列表的順序無關緊要,建議您改用set
s。 它們提供了有效的元素查找,並使執行這樣的操作非常簡單:
>>> players = {'ray': {1,2,3,6,7,8,}, 'al':{1,2,3,4,8,9,}}
>>> lotto = {1,2,3,4,5,6,}
>>> {k: v - lotto for k, v in players.items()}
{'ray': {8, 7}, 'al': {8, 9}}
>>>
您可以這樣過濾:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6]
new_players = {a:[i for i in b if i not in lotto] for a, b in players.items()}
輸出:
{'al': [8, 9], 'ray': [7, 8]}
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