[英]python iterate over a list and remove any duplicates found within lists inside a dictionary and remove the duplicates
我有一个数字列表和一个带有名称(键)和数字(值)的字典,我需要遍历名为lotto的列表,然后对照字典中名称的值检查它们,如果我找到匹配项,则删除该列表字典值中的数字。
这是我到目前为止的东西,但它只是打印出原始的字典键和值
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]
for i in players.values():
if i in lotto:
players.values.remove(i)
print (players)
任何帮助
您以错误的方式访问dict值。 看一下以下内容:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]
for p, val in players.items():
for num in lotto:
if num in val:
players[p].remove(num)
print (players) # {'al': [8, 9], 'ray': [7, 8]}
如果列表值中的项目顺序对您而言并不重要,则可以使用以下更快的变体:
players = {'ray': [1,2,3,6,7,8], 'al':[1,2,3,4,8,9]}
lotto = [1,2,3,4,5,6]
lotto = set(lotto)
for p, val in players.items():
players[p] = list(set(val) - lotto)
print (players) # {'ray': [8, 7], 'al': [8, 9]}
也可以在以下单行代码中进行压缩(尽管它可以重新创建dict
而不是对其进行修改):
players = {k: list(set(val) - lotto) for k, v in players.items()}
您的问题是您试图从错误的列表中删除号码。 players.values
是每个键的值的列表,而不是每个键的单个值的列表 。 使用每个键的单独值:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto = [1,2,3,4,5,6,]
for key, value in players.items():
for i in lotto:
if i in value:
value.remove(i)
print(players)
然后可以通过使用字典理解来缩短:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6,]
players = {k: list(set(v) - set(lotto)) for k, v in players.items()}
print(players) # {'ray': [8, 7], 'al': [8, 9]}
另外,如果程序中列表的顺序无关紧要,建议您改用set
s。 它们提供了有效的元素查找,并使执行这样的操作非常简单:
>>> players = {'ray': {1,2,3,6,7,8,}, 'al':{1,2,3,4,8,9,}}
>>> lotto = {1,2,3,4,5,6,}
>>> {k: v - lotto for k, v in players.items()}
{'ray': {8, 7}, 'al': {8, 9}}
>>>
您可以这样过滤:
players = {'ray': [1,2,3,6,7,8,], 'al':[1,2,3,4,8,9,]}
lotto =[1,2,3,4,5,6]
new_players = {a:[i for i in b if i not in lotto] for a, b in players.items()}
输出:
{'al': [8, 9], 'ray': [7, 8]}
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