[英]How to get Jscroll plugin ajax response in callback function
嘗試在回調函數中獲取jscroll響應,查找響應中收到的url,以便可以在滾動時更新它並獲取頁面視圖。
<script type="text/javascript">
$('.next-btncall').jscroll({
debug: false,
autoTrigger: true,
autoTriggerUntil: false,
loadingHtml: '<img src="/static/images/loading.svg" alt="Loading" /> Loading...',
loadingFunction: false,
padding: 20,
nextSelector: 'a.jscroll-next:last',
contentSelector: '.endless-col',
pagingSelector: '',
callback: urlUpdate(data)
});
function urlUpdate(contentSelector) {
console.log('responose of ajax');
window.history.pushState(null, null, url);
}
嘗試這個
$('.next-btncall').jscroll({ contentSelector: '.endless-col', callback: function(data) { window.history.pushState(null, null, data.replace(' .endless-col', '')); } });
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