[英]JavaScript Storing Data in 2-D Array
我想檢查數據數組中的元素,如果它在表中包含該月份和數字,則顯示為“ O”。 因此,對於“ Jan-1”, Array1[0][0]
應該顯示為“ O”,但下面的代碼不起作用。 有人能幫我嗎?
var Data = ["Jan-1", "Feb-4", "Apr-5"];
var Month= ["Jan", "Feb", "Mar", "Apr", "May"];
var Number = ["1", "2", "3", "4", "5"];
var Array1 = [[]];
for (var k = 0; k < Data.length; k++) {
var split = Data[k].split("-");
for (var z = 0; z < Month.length; z++) {
for (var s = 0; s < Number.length; s++) {
if (Month[z] == split[0] && period[s] == split[1]) {
Array1[z][s] = "O";
} else {
Array1[z][s] = "X";
}
}
}
}
number/month | Jan | Feb | Mar | Apr | May
------------------------------------------------------
1 | O | X | X | X | X
2 | X | X | X | X | X
3 | X | X | X | X | X
4 | X | O | X | X | X
5 | X | X | X | O | X
您應該遍歷Number
和Month
數組,並每次檢查是否Month[j] + "-" + Number[i]
在Data
數組中:
var Data = ["Jan-1", "Feb-4", "Apr-5"]; var Month = ["Jan", "Feb", "Mar", "Apr", "May"]; var Number = ["1", "2", "3", "4", "5"]; var result = []; for (var i = 0; i < Number.length; i++) { // foreach number result[i] = []; // create a row for this current number for (var j = 0; j <Month.length; j++) { // for each month if (Data.indexOf(Month[j] + "-" + Number[i]) !== -1) { // check if the current combination (currentMonth-currentNumber) is in the Data array result[i][j] = "O"; } else { result[i][j] = "X"; } } } result.forEach(function(row) { console.log(row.join(" | ")); });
分析您的代碼:
var Data = ["Jan-1", "Feb-4", "Apr-5"];
var Month= ["Jan", "Feb", "Mar", "Apr", "May"];
var Number = ["1", "2", "3", "4", "5"];
var Array1 = [ ["X","X","X","X","X"], ["X","X","X","X","X"], "X","X","X","X","X"], ["X","X","X","X","X"], ["X","X","X","X","X"]]; //Initialise all elements to "X" by default. We shall change only those indexes that match.
for (var k = 0; k < Data.length; k++) {
var split = Data[k].split("-");
for (var z = 0; z < Month.length; z++) {
for (var s = 0; s < Number.length; s++) {
if (Month[z] == split[0] && Number[s] == split[1]) {
Array1[z][s] = "O";
} else {
//Array1[z][s] = "X"; Do not change here as the loop will go over the entire array once for each data. Hence previous matches would get lost!!
}
}
}
}
最后, console.table(Array1);
打印值。
注釋:初始化時,您將行聲明為月,將列聲明為天,但預期輸出相反。 因此,要生成預期的輸出,請在定義值時打印橫向形式或更改:
if (Month[z] == split[0] && Number[s] == split[1]) {
Array1[s][z] = "O";
}
您可以使用具有給定數據的對象,並迭代month
和number
以返回帶有'O'
或'X'
信息的新數組。
var data = ["Jan-1", "Feb-4", "Apr-5"], month = ["Jan", "Feb", "Mar", "Apr", "May"], number = ["1", "2", "3", "4", "5"], result = [], hash = Object.create(null); data.forEach(function(s) { var [m, d] = s.split('-'); hash[m] = hash[m] || {}; hash[m][d] = true; }); result = month.map(function (m, z) { return number.map(function (s) { return (hash[m] || {})[s] ? 'O' : 'X'; }); }); console.log(result);
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