我可以使用函數 'count()' 來查找密碼中的大寫字母數量嗎？ （蟒蛇）

Question

當我輸入下面的代碼時，它說：

類型錯誤：必須是 str，而不是列表

這是否意味着我不能使用函數 count() 或者還有其他方法可以對其進行編程嗎？

password = "CheeseMakesMeHappy"
uppercase =["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
print (password.count(uppercase))

Answer 1

只需檢查密碼中的每個字符並檢查它是否是大寫字符。 例如：

password = "FoOoObA"
print(len([c for c in password if c.isupper()]))
>> 4

另一種方法是使用集合和位掩碼來計算唯一大寫字符的數量。

password = "CheeseMakesMeHappy"
uppercase = set(["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"])
print(len(set(password)&uppercase))
>> 3

然而， set解決方案只會計算 UNIQUE 字符，但在密碼強度計量的情況下，這可能不是一個壞主意。

Answer 2

問題在於方法count()需要一個字符串對象。 現在，通過這一行(password.count(uppercase)) ，您可以有效地將 Array 對象傳遞給您的函數。 請參閱 zeraien 的答案以獲得一個好的解決方案。