[英]access count number of records with criteria celebrity
我一直在尋找解決問題的方法,希望您能幫到我,我有一張桌子,上面有兩列,一個是名字,兩個是一個城鎮,我需要從埃皮特計算莎拉的次數,但是重復的次數是技巧我需要下面的表2這樣的結果
Name town
Sarah Egypt
John Germany
Mick France
Sarah Egypt
Sarah USA
John Germany
Mick France
John Germany
Name town duplicate
Sarah Egypt 1
John Germany 1
Mick France 1
Sarah Egypt 2
Sarah USA 1
John Germany 2
Mick France 2
John Germany 3
您應該使用聚合函數count(*)並進行分組
select name, town, count(*) as duplicated
from my_table
group by name, town
嘗試這個,
創建表:
create table test (name varchar(20), town varchar(20));
插入語句:
insert into test value('Sarah','Egypt');
insert into test values('John','Germany');
insert into test values('Mick','France');
insert into test values('Sarah','Egypt');
insert into test values('Sarah','USA');
insert into test values('John','Germany');
insert into test values('Mick','France');
insert into test values('Sarah','Egypt');
查詢:
set @x=1;
set @checkname='';
set @checktown='';
select name, town ,row_number
from ( select name, town, if(@checkname = name && @checktown = town,@x := @x + 1 ,@x := 1) as row_number,
@checkname := name, @checktown := town
from test
order by name, town
) a
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