如何在python中將文本文件讀取為列表列表

Question

我有一個像這樣分成不同行的大文本文件：

35 4 23 12 8 \\n 23 6 78 3 5 \\n 27 4 9 10 \\n 73 5 \\n

我需要將其轉換為列表列表，每一行都是一個單獨的元素，如下所示：

[[35, 4, 23, 12, 8], [23, 6, 78, 3, 5], [27, 4, 9, 10], [73, 5], ....]

Answer 1

這可能就是你要找的...

with open('file_to_read.csv', 'rU') as f:
        l1 = []
        for ele in f:
            line = ele.split('\n')
            l1.append(line)
print(l1)

Answer 2

您可能只能使用numpy的genfromtxt方法來執行此操作。

from numpy import genfromtxt 
lol = genfromtxt('myFile.csv', delimiter=' ')

在此處查找更多信息。

Answer 3

lines = [line.split() for line in open('yourtextfile.txt')]  # opens the text file and calls .split() on every line, effectively splitting on every space, creating a list of numbers.

或者，以下內容也會將您的值轉換為 int：

lines = [[int(v) for v in line.split()] for line in open('yourtextfile.txt')] # opens the text file and calls .split() on every line, effectively splitting on every space, creating a list of numbers that are converted to int()