如何在python中将文本文件读取为列表列表

Question

我有一个像这样分成不同行的大文本文件：

35 4 23 12 8 \\n 23 6 78 3 5 \\n 27 4 9 10 \\n 73 5 \\n

我需要将其转换为列表列表，每一行都是一个单独的元素，如下所示：

[[35, 4, 23, 12, 8], [23, 6, 78, 3, 5], [27, 4, 9, 10], [73, 5], ....]

Answer 1

这可能就是你要找的...

with open('file_to_read.csv', 'rU') as f:
        l1 = []
        for ele in f:
            line = ele.split('\n')
            l1.append(line)
print(l1)

Answer 2

您可能只能使用numpy的genfromtxt方法来执行此操作。

from numpy import genfromtxt 
lol = genfromtxt('myFile.csv', delimiter=' ')

在此处查找更多信息。

Answer 3

lines = [line.split() for line in open('yourtextfile.txt')]  # opens the text file and calls .split() on every line, effectively splitting on every space, creating a list of numbers.

或者，以下内容也会将您的值转换为 int：

lines = [[int(v) for v in line.split()] for line in open('yourtextfile.txt')] # opens the text file and calls .split() on every line, effectively splitting on every space, creating a list of numbers that are converted to int()