Python RegEx刪除新行（不應存在）

Question

我提取了一些文本，希望通過RegEx進行清理。

我已經學習了基本的RegEx，但是不確定如何構建此RegEx：

str = '''
this is 
a line that has been cut.
This is a line that should start on a new line
'''

應該轉換為：

str = '''
this is a line that has been cut.
This is a line that should start on a new line
'''

這個r'\\w\\n\\w'似乎抓住了它，但不確定如何用空格替換新行並且不觸摸單詞的結尾和開頭

Answer 1

您可以將此正則表達式后面的代碼用於re.sub ：

>>> str = '''
... this is
... a line that has been cut.
... This is a line that should start on a new line
... '''
>>> print re.sub(r'(?<!\.)\n', '', str)
this is a line that has been cut.
This is a line that should start on a new line
>>>

正則演示

(?<!\\.)\\n匹配所有不帶點號的換行符。

如果您不希望基於點的存在進行匹配，請使用：

re.sub(r'(?<=\w\s)\n', '', str)

RegEx演示2