Python RegEx删除新行（不应存在）

Question

我提取了一些文本，希望通过RegEx进行清理。

我已经学习了基本的RegEx，但是不确定如何构建此RegEx：

str = '''
this is 
a line that has been cut.
This is a line that should start on a new line
'''

应该转换为：

str = '''
this is a line that has been cut.
This is a line that should start on a new line
'''

这个r'\\w\\n\\w'似乎抓住了它，但不确定如何用空格替换新行并且不触摸单词的结尾和开头

Answer 1

您可以将此正则表达式后面的代码用于re.sub ：

>>> str = '''
... this is
... a line that has been cut.
... This is a line that should start on a new line
... '''
>>> print re.sub(r'(?<!\.)\n', '', str)
this is a line that has been cut.
This is a line that should start on a new line
>>>

正则演示

(?<!\\.)\\n匹配所有不带点号的换行符。

如果您不希望基于点的存在进行匹配，请使用：

re.sub(r'(?<=\w\s)\n', '', str)

RegEx演示2