通過多個程序在Excel文件中進行讀寫

Question

我的任務：

• 從網站獲取數據並將其實時寫入Excel文件（使用Microsoft.Office.Interop.Excel的時間為0.5-1s）

• 當程序將數據寫入Excel文件時，我想使用（Excel或類似的東西）打開該文件以查看數據，圖表...

那么，如何同時讀寫Excel文件呢？ 還是可以使用其他方式？

Answer 1

void ExportToExcel（）{

        try
        {

            SaveFileDialog svg = new SaveFileDialog();

            using (FileStream stream = new FileStream(svg.FileName + ".xlsx", FileMode.Create))
            {
                Microsoft.Office.Interop.Excel.Application excel = new Microsoft.Office.Interop.Excel.Application();
                excel.Visible = true;
                Microsoft.Office.Interop.Excel.Workbook workbook = excel.Workbooks.Add(System.Reflection.Missing.Value);
                Microsoft.Office.Interop.Excel.Worksheet sheet1 = (Microsoft.Office.Interop.Excel.Worksheet)workbook.Sheets[1];
                int StartCol = 1;
                int StartRow = 1;
                int j = 0, i = 0;

                //Write Headers
                for (j = 0; j < dataGridView1.Columns.Count; j++)
                {
                    Microsoft.Office.Interop.Excel.Range myRange = (Microsoft.Office.Interop.Excel.Range)sheet1.Cells[StartRow, StartCol + j];
                    myRange.Value2 = dataGridView1.Columns[j].HeaderText;
                }

                StartRow++;

                //Write datagridview content
                for (i = 0; i < dataGridView1.Rows.Count; i++)
                {
                    for (j = 0; j < dataGridView1.Columns.Count; j++)
                    {
                        try
                        {
                            Microsoft.Office.Interop.Excel.Range myRange = (Microsoft.Office.Interop.Excel.Range)sheet1.Cells[StartRow + i, StartCol + j];
                            myRange.Value2 = dataGridView1[j, i].Value == null ? "" : dataGridView1[j, i].Value.ToString();
                        }
                        catch
                        {
                            ;
                        }
                    }
                }
            }
        }

        catch (Exception ex)
        {
            MessageBox.Show(ex.ToString());
        }

    }