正則表達式排除特定字符串

Question

我需要有一個.NET正則表達式匹配"[@foo]"從"applicant_data/contact_number[@foo]" W / C我已經可以做到使用模式"\\[@(.*?)\\]"

但是我想作一個例外，以便"applicant_data/contact_number[@foo=2]"與模式不匹配。 因此，問題是正則表達式應該是什么，以便它將獲得任何有效的字母數字（[@bar]，[@ theVar]，[@ zoo $ 6]），而不是[@ bar = 1]，[@ theVar = 3] ？

Answer 1

試試這個正則表達式：

\\[@(?![^\\]]*?=).*?\\]

點擊演示

說明：

• \\[@ -匹配[@字面意思
• (?![^\\]]*?=) -前瞻，以確保=在下一個]之前不存在=
• .*? -匹配0+次出現的除換行符以外的任何字符
• \\] -匹配]

Answer 2

您可以嘗試以下方法：

\[@[\w-]+(?!=)\]

說明：

"\[" &       ' Match the character “[” literally
"@" &        ' Match the character “@” literally
"[\w-]" &    ' Match a single character present in the list below
                ' A “word character” (Unicode; any letter or ideograph, digit, connector punctuation)
                ' The literal character “-”
   "+" &        ' Between one and unlimited times, as many times as possible, giving back as needed (greedy)
"(?!" &      ' Assert that it is impossible to match the regex below starting at this position (negative lookahead)
   "=" &        ' Match the character “=” literally
")" &
"\]"         ' Match the character “]” literally

希望這可以幫助！