[英]Get data from database without refreshing the page in ASP.NET
我正在用ASP.net和SQL Server做一個項目。 我正在用戶登錄屏幕上調用存儲過程以驗證用戶身份。 但是,當我調用存儲過程時,需要刷新整個頁面才能獲取數據。
如何在不刷新頁面的情況下實現相同目的?
這是我當前的代碼
sql = "EXEC dbo.sProc_Admin_Auth @UserNm = '" + User + "',@Pwd = '"+Pwd+"'";
cmd = new SqlCommand(sql, cn.connect());
dr = cmd.ExecuteReader();
if(dr.Read())
{
Session["UserId"] = dr["UserId"].ToString();
Session["LoginId"] = User;
Session["UserNm"] = dr["FullNm"].ToString();// "Jayasurya Satheesh";
Session["Email"] = dr["Email"].ToString();
Session["JoinDt"] = dr["CreateDt"].ToString();
Response.Redirect("Index.aspx");
LblError.Visible = false;
}
else
{
LblError.Visible = true;
LblError.Text = "Login Failed!";
}
如果要加載數據而不刷新頁面。 您可以公開webservice方法或創建頁面方法,然后可以通過ajax調用ASP.NET頁面方法
[WebMethod]
public static string Insert_Data(string user, string pwd)
{
sql = "EXEC dbo.sProc_Admin_Auth @UserNm = '" + User + "',@Pwd = '"+Pwd+"'";
cmd = new SqlCommand(sql, cn.connect());
dr = cmd.ExecuteReader();
if(dr.Read())
{
Session["UserId"] = dr["UserId"].ToString();
Session["LoginId"] = User;
Session["UserNm"] = dr["FullNm"].ToString();// "Jayasurya Satheesh";
Session["Email"] = dr["Email"].ToString();
Session["JoinDt"] = dr["CreateDt"].ToString();
Response.Redirect("Index.aspx");
LblError.Visible = false;
}
else
{
LblError.Visible = true;
LblError.Text = "Login Failed!";
}
}
客戶端
$(document).ready(function () {
$('#btnsubmit').click(function () {
var name = $('#user').val();
var sex = $('#pwd').val();
$.ajax({
type: 'POST',
contentType: "application/json; charset=utf-8",
url: 'Default.aspx/Insert_Data',
data: "{'user':'" + user+ "','pwd':'" + pwd + "'}",
async: false,
success: function (response) {
alert("Record saved successfully..!!");
},
error: function () {
alert("Error");
}
});
});
});
使用Ajax Extension ,這是一個簡單的示例:
.aspx文件
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:TextBox runat="server" id="username" name="username" placeholder="Enter Username"></asp:TextBox>
<asp:TextBox name="passwd" ID="passwd" runat="server" placeholder="Enter Password"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Login" onclick="Button1_Click" />
<br />
<asp:Label ID="LblError" runat="server"></asp:Label>
</ContentTemplate>
</asp:UpdatePanel>
</div>
</form>
</body>
</html>
aspx.cs文件-將其添加到登錄按鈕的Click事件
protected void Button1_Click(object sender, EventArgs e)
{
string sql = "";
SqlConnection cn = null;
SqlCommand cmd = null;
SqlDataReader dr = null;
string User = username.Text;
string Pwd = passwd.Text;
//cn = "<< your connection string>>";
try
{
cn.Open();
// Your code
sql = "EXEC dbo.sProc_Admin_Auth @UserNm = '" + User + "',@Pwd = '" + Pwd + "'";
cmd = new SqlCommand(sql, cn);
dr = cmd.ExecuteReader();
if (dr.Read())
{
Session["UserId"] = dr["UserId"].ToString();
Session["LoginId"] = User;
Session["UserNm"] = dr["FullNm"].ToString();// "Jayasurya Satheesh";
Session["Email"] = dr["Email"].ToString();
Session["JoinDt"] = dr["CreateDt"].ToString();
Response.Redirect("Index.aspx");
LblError.Visible = false;
}
else
{
LblError.Visible = true;
LblError.Text = "Login Failed!";
}
}
catch (Exception exce)
{
LblError.Text = exce.Message;
}
finally
{
cn.Close();
}
}
您可以在工具箱-> Ajax擴展下找到UpdatePanel和ScriptManager。
使用try-catch塊來處理運行時異常。
我知道3種可能的方式:
1)使用更新面板:
參見示例: http : //www.aspdotnet-pools.com/2014/07/ajax-login-form-in-aspnet-using-cnet.html
2)使用webmethod:
參見示例: http : //www.aspforums.net/Threads/133296/Develop-simple-AJAX-Login-form-using-jQuery-in-ASPNet/
3)使用分層編碼:
參見示例: https : //www.codeproject.com/Articles/170882/jQuery-AJAX-and-HttpHandlers-in-ASP-NET
我更喜歡方法3編碼,因為它更靈活並且分層編碼概念可移植到其他Web編程平台。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.