如何使用python將字符串分成2個？

Question

我有這些琴弦。

"LAKDOER 567-85 06D-1F"
"QRT1 35-43 459-70 D"
"50201 WSCFVGH 133 9H "
"STREE VDERYG 8C LOP"
"GG-STAR THIEOR- WL-515-67-26548H-9"

我想拆分所有字符串，並需要這樣的輸出。

["LAKDOER", "567-85 06D-1F"]
["QRT1",  "35-43 459-70 D"]
["50201 WSCFVGH", "133 9H "]
["STREE VDERYG", "8C LOP"]
["GG-STAR THIEOR-", "WL-515-67-26548H-9"]

Answer 1

使用re.split()函數和特定的正則表達式模式：

import re

lst = ["LAKDOER 567-85 06D-1F", "QRT1 35-43 459-70 D", "50201 WSCFVGH 133 9H ", 
       "STREE VDERYG 8C LOP", "GG-STAR THIEOR- WL-515-67-26548H-9"
       ]

pat = re.compile(r'\s(?=[a-z-]*[0-9])', re.I)
for s in lst:
    print(pat.split(s, 1))

輸出：

['LAKDOER', '567-85 06D-1F']
['QRT1', '35-43 459-70 D']
['50201 WSCFVGH', '133 9H ']
['STREE VDERYG', '8C LOP']
['GG-STAR THIEOR-', 'WL-515-67-26548H-9']

---

• re.I正則表達式標志，區分大小寫不匹配
• \\s(?=[az-]*[0-9]) -匹配空格字符\\s后跟具有強制編號[0-9]和可選[az-]*序列的字符序列（由正向保證）斷言(?=...) ）