[英]Group items in a list of tuples based on a common ID
我有一個很大的同義詞集(10000+)作為元組列表,看起來像這樣:
data = [
(435347,'cat'),
(435347,'feline'),
(435347,'lion'),
(6765756,'dog'),
(6765756,'hound'),
(6765756,'puppy'),
(435347,'kitten'),
(987977,'frog')
]
其中每個同義詞是由任意的共享ID標識,在此情況下435347
, 6765756
,和987977
。
我想編寫一個使數據看起來像這樣的函數:
processed_data = [
(435347,'cat','feline','lion','kitten'),
(6765756,'dog','hound','puppy'),
(987977,'frog')
]
任何建議,不勝感激!
嘗試這個:
groups = {}
for x, y in data:
group = groups.get(x, [])
group.append(y)
groups[x] = group
print(groups)
輸出:
{987977: ['frog'], 435347: ['cat', 'feline', 'lion', 'kitten'], 6765756: ['dog', 'hound', 'puppy']}
dictionary = {}
for val in data:
id_, name = val
if id_ in dictionary:
dictionary[id_].append(name)
else:
dictionary[id_] = [id_, name]
print(list(dictionary.values()))
>>> [[435347, 'cat', 'feline', 'lion', 'kitten'], [6765756, 'dog', 'hound', 'puppy'], [987977, 'frog']]
您可以嘗試以下一種方法:
data = [(435347,'cat'),(435347,'feline'),(435347,'lion'),(6765756,'dog'),(6765756,'hound'),(6765756,'puppy'),(435347,'kitten'),(987977,'frog')]
dataset = set(i[0] for i in data)
processed_data = sorted([(tuple([i]) + tuple(j[1] for j in data if j[0]==i)) for i in dataset])
print(processed_data)
輸出:
[(435347, 'cat', 'feline', 'lion', 'kitten'), (987977, 'frog'), (6765756, 'dog', 'hound', 'puppy')]
這是另一種方法,是我對另一個問題的回答的修改。 您可以使用reduce
和map
實現此目的:
def reducer(x, y):
if isinstance(x, dict):
ykey, yval = y
if ykey not in x:
x[ykey] = [yval]
else:
x[ykey] += [yval]
return x
else:
xkey, xval = x
ykey, yval = y
a = {xkey: [xval]}
if ykey in a:
a[ykey] += [yval]
else:
a[ykey] = [yval]
return a
processed_data = map(lambda x: (x[0],) + tuple(x[1]), reduce(reducer, data).items())
輸出:
>>> print processed_data
[(987977, 'frog'),
(435347, 'cat', 'feline', 'lion', 'kitten'),
(6765756, 'dog', 'hound', 'puppy')]
說明
逐步分解:
reducer()
函數通過關鍵字將項分組到字典中。 詞典的值是一個列表,該列表后附加同義詞值。
>>> print(reduce(reducer, data))
{435347: ['cat', 'feline', 'lion', 'kitten'],
987977: ['frog'],
6765756: ['dog', 'hound', 'puppy']}
我們在reduce()
函數的輸出上調用.items()
,以將其作為tuples
列表獲取:
>>> print(reduce(reducer, data).items())
[(987977, ['frog']),
(435347, ['cat', 'feline', 'lion', 'kitten']),
(6765756, ['dog', 'hound', 'puppy'])]
最后,我們調用map()
將輸出轉換為所需的形式。
字典可能是更適合您的問題的解決方案:
data = [(435347,'cat'),(435347,'feline'),(435347,'lion'),(6765756,'dog'),(6765756,'hound'),(6765756,'puppy'),(435347,'kitten'),(987977,'frog')]
results = {}
for key, item in data:
results.setdefault(key,[]).append(item)
輸出:
{435347: ['cat', 'feline', 'lion', 'kitten'],
987977: ['frog'],
6765756: ['dog', 'hound', 'puppy']}
setdefault
適合您的情況。 如果鍵不存在,則基本上創建一個字典條目,如果鍵存在,則追加到條目。
有很多方法,其中一些是:
數據是:
data = [
(435347,'cat'),
(435347,'feline'),
(435347,'lion'),
(6765756,'dog'),
(6765756,'hound'),
(6765756,'puppy'),
(435347,'kitten'),
(987977,'frog')
]
Itertools groupby:
from itertools import groupby
print([tuple(i) for j,i in groupby(sorted(data),key=lambda x:x[0])])
集合默認字典:
from collections import defaultdict
d=defaultdict(list)
for i in data:
d[i[0]].append(i)
print(d)
沒有任何模塊:
without_module={}
for i in data:
if i[0] not in without_module:
without_module[i[0]]=[i]
else:
without_module[i[0]].append(i)
print(without_module)
好吧,這是一個建議,所以如果錯了,請不要生氣-
因此,請嘗試創建輸入並創建for語句,然后使其從.txt文件或您喜歡的文件中讀取數據。 並在for下方創建一個if語句。
碼:
animal=input("Animal: ")
f=open("animal.txt")
for line in f:
if genre in line.strip():
print(line)
會親自提出建議,並將數據全部整理成陣列並執行\\ n
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