[英]how to use some html element tag inside the json value
我使用Ajax,js將json數據綁定到html表。 在我的項目中,我有4個表格標題(序號,名稱,年份,下載鏈接)。 前三列同步並正常運行,但沒有錯誤。但是,最后一列我需要帶有鏈接的引導下載按鈕。 我如何使用json做到這一點?
確切地我需要什么:如果我加載頁面,則需要我的名稱,年份,引導下載按鈕和插入的鏈接。
html
<body>
<div class="container">
<div class="first bg-primary">
<h2>A R Rahman All Movies</h2>
<p>Download songs free</p>
</div>
<!-- -->
<table id="personDataTable" class="table table-dark table-hover">
<thead>
<tr>
<th>S.No</th>
<th>Movie Name</th>
<th>Year</th>
<th>Download Link</th>
</tr>
</thead>
</table>
<!-- table end -->
<script>
$.ajax({
//url: 'https://jsonplaceholder.typicode.com/posts',
url: 'https://10rs.000webhostapp.com/json-data.json',
type: "get",
dataType: "json",
success: function (data) {
drawTable(data);
}
});
function drawTable(data) {
for (var i = 0; i < data.length; i++) {
drawRow(data[i]);
}
}
function drawRow(rowData) {
var row = $("<tr />")
$("#personDataTable").append(row);
row.append($("<td>" + rowData.id + "</td>"));
row.append($("<td>" + rowData.name + "</td>"));
row.append($("<td>" + rowData.year + "</td>"));
row.append($("<td>" + rowData.link + "</td>"));
}
</script>
<footer class="bg-danger">
<p>Design and Developed by Rajadurai</p>
</footer>
</div>
<!-- container end -->
</body>
這是數據的輸出
[
{
"id": 1,
"name": "Roja",
"year": "1992",
"link": "<a href="#" class="btn btn-info" role="button">Link Button</a>"
},
{
"id": 2,
"name": "Gentleman",
"year": "1993"
},
{
"id": 3,
"name": "Kizhakku Cheemayile",
"year": "1993"
},
{
"id": 4,
"name": "Pudhiya Mugam",
"year": "1993"
},
{
"id": 5,
"name": "Thiruda Thiruda",
"year": "1993"
}
]
你可以用這個
row.append($("<td><a href='" + rowData.link + "'><button class='btn'>Go</button></a></td>"));
您必須通過僅放置鏈接或用簡單(')代替雙破折號(“)來修改數據中的鏈接
1-如果您只想在數據中放入鏈接
//像這樣修改您的代碼
$.ajax({
//url: 'https://jsonplaceholder.typicode.com/posts',
url: 'https://10rs.000webhostapp.com/json-data.json',
type: "get",
dataType: "json",
success: function (data) {
drawTable(data);
}
});
function drawTable(data) {
for (var i = 0; i < data.length; i++) {
drawRow(data[i]);
}
}
function drawRow(rowData) {
var row = $("<tr />")
$("#personDataTable").append(row);
row.append($("<td>" + rowData.id + "</td>"));
row.append($("<td>" + rowData.name + "</td>"));
row.append($("<td>" + rowData.year + "</td>"));
row.append($("<td><a href='" + rowData.link + "' class='btn btn-info' role='button'>Link Button</a></td>"));
}
2-如果您想用簡單的Cote(')來代替double Cote(“),則無需更改代碼即可使用
最后,我得到了完整的答案,項目運行良好。
的HTML
<div class="container">
<div class="header">
<h2>A R Rahman All Movie Songs</h2>
<p>Download songs free</p>
</div>
<!-- header end -->
<div class="table-responsive-md">
<table id="personDataTable" class="table table-dark">
<thead>
<tr>
<th>S.No</th>
<th>Movie Name</th>
<th>Year</th>
<th>Download</th>
</tr>
</thead>
</table>
</div>
<!-- table end -->
<footer class="bg-success">
<p style="color:#ffffff;">Design and Developed by
<span style="color:red;background-color:yellow;">Rajadurai</span>
</p>
</footer>
</div>
JAVASCRIPT
<script>
$.ajax({
//url: 'https://jsonplaceholder.typicode.com/posts',
url: 'https://10rs.000webhostapp.com/ar/json-data.json',
//url: 'json-data.json',
type: "get",
dataType: "json",
success: function (data) {
drawTable(data);
}
});
function drawTable(data) {
for (var i = 0; i < data.length; i++) {
drawRow(data[i]);
}
}
function drawRow(rowData) {
var row = $("<tr />")
$("#personDataTable").append(row);
row.append($("<td>" + rowData.id + "</td>"));
row.append($("<td>" + rowData.title + "</td>"));
row.append($("<td>" + rowData.year + "</td>"));
row.append($("<td><a href='" + rowData.link + "' class='btn btn-info' role='button' target='_blank'>Download</a></td>"));
}
</script>
JSON格式
[{
"id": 1,
"title": "Roja",
"year": "1992"
},
{
"id": 2,
"title": "Gentleman",
"year": "1993"
},
{
"id": 3,
"title": "Kizhakku Cheemayile",
"year": "1993"
},
{
"id": 4,
"title": "Pudhiya Mugam",
"year": "1993"
},
{
"id": 5,
"title": "Thiruda Thiruda",
"year": "1993"
}]
輸出值
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