Django CharField未定義

Question

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = CharField(max_length=100)
    submitter = CharField(max_length=100)
    species = CharField(max_length=30)
    breed = CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)

通過此代碼，運行“ python manage.py makemigrations”時出現命令行錯誤。 未定義名稱“ CharField”。

如何解決。

Answer 1

您在某些聲明中直接使用了CharField而不是models.CharField 。

應該這樣做：

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = models.CharField(max_length=100)
    submitter = models.CharField(max_length=100)
    species = models.CharField(max_length=30)
    breed = models.CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)

Answer 2

您應該將CharField類添加到模塊導入中，即

from django.db import models
from django.db.models import CharField

但是，這不是在項目中導入模塊的正確方法。 因此，如下更改您的models.py ，

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = models.CharField(max_length=100)
    submitter = models.CharField(max_length=100)
    species = models.CharField(max_length=30)
    breed = models.CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)

Answer 3

不應該是這樣的：

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = models.CharField(max_length=100)
    submitter = models.CharField(max_length=100)
    species = models.CharField(max_length=30)
    breed = models.CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)