Django CharField未定义

Question

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = CharField(max_length=100)
    submitter = CharField(max_length=100)
    species = CharField(max_length=30)
    breed = CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)

通过此代码，运行“ python manage.py makemigrations”时出现命令行错误。 未定义名称“ CharField”。

如何解决。

Answer 1

您在某些声明中直接使用了CharField而不是models.CharField 。

应该这样做：

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = models.CharField(max_length=100)
    submitter = models.CharField(max_length=100)
    species = models.CharField(max_length=30)
    breed = models.CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)

Answer 2

您应该将CharField类添加到模块导入中，即

from django.db import models
from django.db.models import CharField

但是，这不是在项目中导入模块的正确方法。 因此，如下更改您的models.py ，

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = models.CharField(max_length=100)
    submitter = models.CharField(max_length=100)
    species = models.CharField(max_length=30)
    breed = models.CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)

Answer 3

不应该是这样的：

from django.db import models

class Pet(models.Model):
    SEX_CHOICES = [('M','Male'), ('F', 'Female')]
    name = models.CharField(max_length=100)
    submitter = models.CharField(max_length=100)
    species = models.CharField(max_length=30)
    breed = models.CharField(max_length=30, blank=True)
    description = models.TextField()
    sex = models.CharField(choices=SEX_CHOICES, max_length=1, blank=True)
    submission_date = models.DateTimeField()
    age = models.IntegerField(null=True)
    vaccinations = models.ManyToManyField('Vaccine', blank=True)


class Vaccine(models.Model):
    name = models.CharField(max_length=50)