Perl從外部程序發送STDIN和過濾STDOUT

Question

我正在為另一個應用程序編寫Perl包裝器。

我需要管道STDIN和一些STDOUT。

Perl代碼

#!/usr/bin/perl -w

use strict;

use IPC::Run3 qw(run3);

my $stdout;

local $| = 1;

run3 ['node','gekko',"-b","-c","BNB-XLM-Doktor_v1-5-144-config.js"],  undef, $stdout;

輸出量

2018-03-18 13:50:10 (DEBUG):    Available 142534
2018-03-18 13:50:10 (DEBUG):    Optimal 144240
2018-03-18 13:50:10 (INFO): The database has 1707 candles missing, Figuring out which ones...
2018-03-18 13:50:11 (INFO): Gekko detected multiple dateranges in the locally stored history. Please pick the daterange you are interested in testing:
2018-03-18 13:50:11 (INFO):          OPTION 1:
2018-03-18 13:50:11 (INFO):      from: 2017-12-08 07:04:00
2018-03-18 13:50:11 (INFO):      to: 2018-03-14 19:04:00
2018-03-18 13:50:11 (INFO):          OPTION 2:
2018-03-18 13:50:11 (INFO):      from: 2018-03-16 00:04:00
2018-03-18 13:50:11 (INFO):      to: 2018-03-18 10:04:00
prompt: option: 

我要實現此STDOUT：

OPTION 1:
from: 2017-12-08 07:04:00
to: 2018-03-14 19:04:00
OPTION 2:
from: 2018-03-16 00:04:00
to: 2018-03-18 10:04:00
prompt: option: 

因此，必須對STDOUT進行過濾，而且我不知道該怎么做。

我用$stdout =~ s/....//g嘗試了，但是沒有用。

請記住，在過濾STDOUT之后，它也必須從父級向子級發送STDIN

Answer 1

您可以為stdout指定一個sub而不是一個文件句柄，它將輸出的每一行作為參數：

#!/usr/bin/perl
use warnings;
use strict;

use IPC::Run3 qw(run3);

my $stdout;
local $| = 1;
run3 ['command'], undef, sub {
    $_ = shift;
    return unless /(?:OPTION \d+|from|to|option):\s+/;

    s/.*INFO\):\s+//;
    print
};