[英]Pandas Replace Values with Dictionary
我有一個具有以下結構的數據框:
Ranges Relative_17-Aug Relative_17-Sep Relative_17-Oct
0 (0.0, 0.1] 1372 1583 1214
1 (0.1, 0.2] 440 337 648
2 (0.2, 0.3] 111 51 105
3 (0.3, 0.4] 33 10 19
4 (0.4, 0.5] 16 4 9
5 (0.5, 0.6] 7 7 1
6 (0.6, 0.7] 4 3 0
7 (0.7, 0.8] 5 1 0
8 (0.8, 0.9] 2 3 0
9 (0.9, 1.0] 2 0 1
10 (1.0, 2.0] 6 0 2
我正在嘗試使用下面的代碼用字典替換列范圍,但是它不起作用,如果我做錯了任何提示:
mydict= {"(0.0, 0.1]":"<=10%","(0.1, 0.2]":">10% and <20%","(0.2, 0.3]":">20% and <30%", "(0.3, 0.4]":">30% and <40%", "(0.4, 0.5]":">40% and <50%", "(0.5, 0.6]":">50% and <60%", "(0.6, 0.7]":">60% and <70%", "(0.7, 0.8]":">70% and <80%", "(0.8, 0.9]":">80% and <90%", "(0.9, 1.0]":">90% and <100%", "(1.0, 2.0]":">100%"}
t_df["Ranges"].replace(mydict,inplace=True)
謝謝!
我認為這是在cut
中創建Ranges
列時最好使用參數labels
:
labels = ['<=10%','>10% and <20%', ...]
#change by your bins
bins = [0,0.1,0.2...]
t_df['Ranges'] = pd.cut(t_df['col'], bins=bins, labels=labels)
如果不可能的話,強制轉換為字符串應該有助於在注釋中建議@Dark,以便使用map
獲得更好的性能:
t_df["Ranges"] = t_df["Ranges"].astype(str).map(mydict)
通過使用map
功能,可以很容易地以一種簡單的方式實現,如下所示。
mydict= {"(0.0, 0.1]":"<=10%","(0.1, 0.2]":">10% and <20%","(0.2, 0.3]":">20% and <30%", "(0.3, 0.4]":">30% and <40%", "(0.4, 0.5]":">40% and <50%", "(0.5, 0.6]":">50% and <60%", "(0.6, 0.7]":">60% and <70%", "(0.7, 0.8]":">70% and <80%", "(0.8, 0.9]":">80% and <90%", "(0.9, 1.0]":">90% and <100%", "(1.0, 2.0]":">100%"}
t_df["Ranges"] = t_df["Ranges"].map(lambda x : mydict[str(x)])
希望這可以幫助..!!
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