[英]Create a new object using the inference rules
我有一個語義網絡。 是否可以使用jena框架基於某些規則在語義網中創建新對象。 例如,有一個具有特定屬性的對象,那么您需要創建一個新對象並在它們之間建立連接。 可能嗎?
是的,這在耶拿的規則系統中是可能的。 通常,我們使用makeSkolem
Reasoner Builtin Primitive創建此類節點:
[example:
(?a urn:ex:owns ?b)
makeSkolem(?ownership,?a,?b)
->
(?a urn:ex:hasOwnership ?ownership)
(?ownership urn:ex:of ?b)
]
這將在圖中創建一個新的空白節點,該節點將用於驗證<urn:ex:owns>
三元組。 例如,當給定一個包含三元組<urn:ex:a> <urn:ex:owns> <urn:ex:b>
作為輸入的圖形時,上述規則將生成以下圖形結構:
<urn:ex:a> <urn:ex:hasOwnership> [
<urn:ex:of> <urn:ex:b>
].
如果您有一些生成URI的方案,那么您也可以在規則中構造URI。
假設so.rules
存在於您的類路徑中並包含上述規則,則以下Java代碼將演示此任務的自定義規則。
// Obtains a list of rules to pass to a rule-based reasoner
// These rules are read from a file.
// This is the most common case.
final List<Rule> rules;
try (final InputStream src = Resources.getResource("so.rules").openStream()) {
rules = Rule
.parseRules(Rule.rulesParserFromReader(new BufferedReader(new InputStreamReader(src))));
}
// Create a rule-based reasoner.
// There are multiple types of reasoners available.
// You may prefer some over others (e.g., when performing OWL inference in tandem with custom rules)
final GenericRuleReasoner reasoner =
(GenericRuleReasoner) GenericRuleReasonerFactory.theInstance().create(null);
reasoner.setRules(rules);
// Create a RDF Model to store data in.
// Create an inference model to interact with.
// The inference model will store any added data in the base model.
// The inference model will store inferred triples internally.
final Model baseModel = ModelFactory.createDefaultModel();
final InfModel model = ModelFactory.createInfModel(reasoner, baseModel);
model.prepare();
// Stimulate the rule by introducing the desired triples to the graph
// :a :owns :b
final Property owns = model.createProperty("urn:ex:", "owns");
final Property hasOwnership = model.createProperty("urn:ex:","hasOwnership");
final Property of = model.createProperty("urn:ex:","of");
final Resource a = model.createResource("urn:ex:a");
final Resource b = model.createResource("urn:ex:b");
model.add(a,owns,b);
// Verify that the rule has fired. That is, that we have created some node
// and that the node relates our other two resources
// -> :a :hasOwnership [ :of :b ]
assertTrue(a.hasProperty(hasOwnership));
final Resource createdObject = a.getPropertyResourceValue(hasOwnership);
assertTrue(createdObject.hasProperty(of,b));
如果您的需求相當簡單,則可以使用SPARQL CONSTRUCT查詢,即
CONSTRUCT { ?p :hasGrandfather ?g . }
WHERE {
?p :hasParent ?parent .
?parent :hasParent ?g .
?g :gender :male .
}
將導致生成三元組以聲明祖父關系。
如果您的需求更復雜,則可以使用SHACL來實現,而SHACL可以在Jena之上實現 。 我將舉一個簡短的例子。 假定您具有以下RDF數據:
@prefix ex: <http://example.com/ns#> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
ex:InvalidRectangle
a ex:Rectangle .
ex:NonSquareRectangle
a ex:Rectangle ;
ex:height 2 ;
ex:width 3 .
ex:SquareRectangle
a ex:Rectangle ;
ex:height 4 ;
ex:width 4 .
為此,您定義了以下形狀文件:
@prefix ex: <http://example.com/ns#> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
@prefix dash: <http://datashapes.org/dash#> .
@prefix sh: <http://www.w3.org/ns/shacl#> .
@prefix xsd: <http://www.w3.org/2001/XMLSchema#> .
ex:Rectangle
a rdfs:Class, sh:NodeShape ;
rdfs:label "Rectangle" ;
sh:property [
sh:path ex:height ;
sh:datatype xsd:integer ;
sh:maxCount 1 ;
sh:minCount 1 ;
sh:name "height" ;
] ;
sh:property [
sh:path ex:width ;
sh:datatype xsd:integer ;
sh:maxCount 1 ;
sh:minCount 1 ;
sh:name "width" ;
] ;
sh:rule [
a sh:TripleRule ;
sh:subject sh:this ;
sh:predicate rdf:type ;
sh:object ex:Square ;
sh:condition ex:Rectangle ;
sh:condition [
sh:property [
sh:path ex:width ;
sh:equals ex:height ;
] ;
] ;
] .
它將生成以下RDF數據:
@prefix owl: <http://www.w3.org/2002/07/owl#> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix xsd: <http://www.w3.org/2001/XMLSchema#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
<http://example.com/ns#SquareRectangle>
a <http://example.com/ns#Square> .
您可以將其添加到RDF存儲中。
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