System.InvalidCastException：'指定的強制轉換無效。

Question

我正在嘗試使用下面的代碼使用memorystream和filestream和一個結構讀取二進制文件：

BinaryFormatter formatter = new BinaryFormatter();
MemoryStream mStream = new MemoryStream();
byte[] buffer = null;
long numBytes = new FileInfo(filename1).Length;
FileStream fs = new FileStream(filename1, FileMode.Open, FileAccess.Read);
BinaryReader br = new BinaryReader(fs);
buffer = br.ReadBytes((int)numBytes);
mStream.Write(buffer, 0, buffer.Length);
mStream.Position = 0;
GameSaved newdata = (GameSaved)formatter.Deserialize(mStream);
mStream.Close();
fs.Close();
fs.Dispose();
mStream.Dispose();

GameSaved結構如下所示：

[Serializable]
struct GameSaved
{
    public int Num_Of_Saved_Game;
    public string[] Name_Of_Saved_Game;
}

但是代碼拋出錯誤

System.InvalidCastException：'指定的強制轉換無效。

編輯：這就是我保存GameSaved結構的方法：

buffer = null;
formatter = new BinaryFormatter();
mStream = new MemoryStream();
formatter.Serialize(mStream, newdata);
buffer = mStream.ToArray();
mStream.Close();
filename = "name.sav";
curFile = @"c:\C#\Try_To_Save_MS\Try_To_Save_MS\bin\Debug\name.sav";

if (File.Exists(curFile))
    File.Delete(curFile);

fs = new FileStream(filename, FileMode.Create, FileAccess.Write);
fs.Write(buffer, 0, (int)buffer.Length);
fs.Dispose();
mStream.Dispose();

誰能告訴我解決問題的方法嗎？

最好的祝福

Answer 1

您應該使用BinaryFormatter.Serialize方法來序列化對象。 在您的代碼中，您編寫了一個緩沖區，但可能不會做同樣的事情

可以以這種方式編寫數據序列化的樣本

GameSaved reloaded = new GameSaved();
void Main()
{
    GameSaved game = new GameSaved();
    game.Num_Of_Saved_Game = 2;
    game.Name_Of_Saved_Game = new string[] {"game1", "game2"};

    Serialize(@"e:\temp\serialize.bin", game);
    Deserialize(@"e:\temp\serialize.bin");

    Console.WriteLine("Games:" + reloaded.Num_Of_Saved_Game);
    foreach(string s in reloaded.Name_Of_Saved_Game)
        Console.WriteLine(s);
}

void Deserialize(string filename1)
{
    BinaryFormatter formatter = new BinaryFormatter();
    using(FileStream fs = new FileStream(filename1, FileMode.Open, FileAccess.Read))
        reloaded = (GameSaved)formatter.Deserialize(fs);
}
void Serialize(string filename1, GameSaved game)
{
    BinaryFormatter formatter = new BinaryFormatter();
    using (FileStream fs = new FileStream(filename1, FileMode.OpenOrCreate, FileAccess.Write))
        formatter.Serialize(fs, game);

}
[Serializable]
struct GameSaved
{
    public int Num_Of_Saved_Game;
    public string[] Name_Of_Saved_Game;
}