[英]Find intersection of two columns in Python Pandas -> list of strings
我想計算A列和B列相交的實例數。 A列和B列中的行是字符串列表。 例如,列A可以包含[汽車,乘客,卡車],列B可以包含[汽車,房屋,花卉,卡車]。 由於在這種情況下,2個字符串重疊,列C應顯示 - > 2
我試過了(這些都沒有):
df['unique'] = np.unique(frame[['colA', 'colB']])
要么
def unique(colA, colB):
unique1 = list(set(colA) & set(colB))
return unique1
df['unique'] = df.apply(unique, args=(df['colA'], frame['colB']))
TypeError :('unique()需要2個位置參數,但3個被賦予','發生在索引文章')
我相信在列表理解中需要set.intersection
length
:
df['C'] = [len(set(a).intersection(b)) for a, b in zip(df.A, df.B)]
要么:
df['C'] = [len(set(a) & set(b)) for a, b in zip(df.A, df.B)]
樣品 :
df = pd.DataFrame(data={'A':[['car', 'passenger', 'truck'], ['car', 'truck']],
'B':[['car', 'house', 'flower', 'truck'], ['car', 'house']]})
print (df)
A B
0 [car, passenger, truck] [car, house, flower, truck]
1 [car, truck] [car, house]
df['C'] = [len(set(a).intersection(b)) for a, b in zip(df.A, df.B)]
print (df)
A B C
0 [car, passenger, truck] [car, house, flower, truck] 2
1 [car, truck] [car, house] 1
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