如何在python中用逗號分隔數字組？

Question

我有以下文字：

Cluster 7: {4, 15, 21, 28, 33, 35, 43, 47, 53, 57, 59, 66,
       69, 70, 74, 86, 87, 88, 90, 114, 136, 148, 201,
       202, 212, 220, 227, 250, 252, 253, 259, 262, 267,
       270, 282, 296, 318, 319, 323, 326, 341}
Cluster 8: {9, 10, 11, 20, 39, 55, 79, 101, 108, 143, 149,
       221, 279, 284, 285, 286, 287, 327, 333, 334, 335,
       336}
Cluster 9: {3, 64, 83, 93, 150, 153, 264, 269, 320, 321, 322}
Cluster 10: {94, 123, 147}

我想通過群集提取每組中的數字。

我嘗試使用正則表達式沒有太多運氣

我努力了：

regex="(Cluster \d+): \{((\d+)[,\}][\n ]+)+|(?:(\d+),[\n ])"

但這些團體並不匹配。

我希望輸出為：

["Cluster 7", '4', '15', '21', '28', '33', '35', '43', '47', '53', '57', '59', '66', '69', '70', '74', '86', '87', '88', '90', '114', '136', '148', '201', '202', '212', '220', '227', '250', '252', '253', '259', '262', '267', '270', '282', '296', '318', '319', '323', '326', '341', "Cluster 8", '9', '10', '11', '20', '39', '55', '79', '101', '108', '143', '149', '221', '279', '284', '285', '286', '287', '327', '333', '334', '335', '336', "Cluster 9", '3', '64', '83', '93', '150', '153', '264', '269', '320', '321', '322', "Cluster 10", "94", "123", "147"]

或者這可能不是最好的方法。

謝謝

Answer 1

我不會使用正則表達式。 您的文本在yaml規范內，可以直接使用保留訂單的yaml加載程序（如oyaml）加載 。

import oyaml as yaml   # pip install oyaml
data = yaml.load(text)

要將該dict解壓縮到所需的“平面”結構，它只是一個列表理解：

[x for (k, v) in data.items() for x in (k, *v)]

_{注意：我是oyaml的作者。}

Answer 2

您可以創建更通用的正則表達式：

import re
s = '\nCluster 7: {4, 15, 21, 28, 33, 35, 43, 47, 53, 57, 59, 66,\n       69, 70, 74, 86, 87, 88, 90, 114, 136, 148, 201,\n       202, 212, 220, 227, 250, 252, 253, 259, 262, 267,\n       270, 282, 296, 318, 319, 323, 326, 341}\nCluster 8: {9, 10, 11, 20, 39, 55, 79, 101, 108, 143, 149,\n       221, 279, 284, 285, 286, 287, 327, 333, 334, 335,\n       336}\nCluster 9: {3, 64, 83, 93, 150, 153, 264, 269, 320, 321, 322}\nCluster 10: {94, 123, 147}\n'
data = re.findall('Cluster \d+|\d+', s)

輸出：

['Cluster 7', '4', '15', '21', '28', '33', '35', '43', '47', '53', '57', '59', '66', '69', '70', '74', '86', '87', '88', '90', '114', '136', '148', '201', '202', '212', '220', '227', '250', '252', '253', '259', '262', '267', '270', '282', '296', '318', '319', '323', '326', '341', 'Cluster 8', '9', '10', '11', '20', '39', '55', '79', '101', '108', '143', '149', '221', '279', '284', '285', '286', '287', '327', '333', '334', '335', '336', 'Cluster 9', '3', '64', '83', '93', '150', '153', '264', '269', '320', '321', '322', 'Cluster 10', '94', '123', '147']

Answer 3

請參閱此處使用的正則表達式

\w+(?: +\w+)?

• \\w+匹配一個或多個單詞字符
• (?: +\\w+)? 可選擇匹配以下內容
  • +匹配一個或多個空格
  • \\w+匹配一個或多個單詞字符

請參閱此處使用的代碼

import re

s = "Cluster 7: {4, 15, 21, 28, 33, 35, 43, 47, 53, 57, 59, 66,\n       69, 70, 74, 86, 87, 88, 90, 114, 136, 148, 201,\n       202, 212, 220, 227, 250, 252, 253, 259, 262, 267,\n       270, 282, 296, 318, 319, 323, 326, 341}\nCluster 8: {9, 10, 11, 20, 39, 55, 79, 101, 108, 143, 149,\n       221, 279, 284, 285, 286, 287, 327, 333, 334, 335,\n       336}\nCluster 9: {3, 64, \n3, 93, 150, 153, 264, 269, 320, 321, 322}\nCluster 10: {94, 123, 147}"
print(re.findall(r"\w+(?: +\w+)?", s))

結果：

['Cluster 7', '4', '15', '21', '28', '33', '35', '43', '47', '53', '57', '59', '66', '69', '70', '74', '86', '87', '88', '90', '114', '136', '148', '201', '202', '212', '220', '227', '250', '252', '253', '259', '262', '267', '270', '282', '296', '318', '319', '323', '326', '341', 'Cluster 8', '9', '10', '11', '20', '39', '55', '79', '101', '108', '143', '149', '221', '279', '284', '285', '286', '287', '327', '333', '334', '335', '336', 'Cluster 9', '3', '64', '83', '93', '150', '153', '264', '269', '320', '321', '322', 'Cluster 10', '94', '123', '147']